An aluminum cup of \(110 \mathrm{~cm}^{3}\) capacity is filled with glycerin at \(22^{\circ} \mathrm{C}\). How much glycerin, if any, will spill out of the cup if the temperature of the cup and glycerin is raised to \(28^{\circ} \mathrm{C}\) ? (The coefficient of volume expansion of glycerin is \(5.1 \times\) \(\left.10^{-4} / \mathrm{C}^{\circ} .\right)\)

Short Answer

Expert verified
By the increase in temperature, the volume of glycerin increased by 3.366 cm^3. So, this amount of glycerin will spill out of the cup.

Step by step solution

01

Identify the knowns and unknowns

From the problem, the initial volume of glycerin V0 = 110 cm^3, β = 5.1x10^-4 /°C, initial temperature = 22°, final temperature = 28°C. Our aim is to calculate ∆V.
02

Calculate the change in temperature

Calculate the change in temperature using the formula ∆T = Final temperature - Initial temperature. Therefore we get ∆T = 28°C - 22°C = 6°C.
03

Calculate the change in volume

Substitute the values of β, V0 and ∆T in the formula for volume expansion ∆V = βV0∆T. Therefore we get ∆V = 5.1x10^-4 /°C x 110 cm^3 x 6°C = 3.366 cm^3.

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