What are the weight in newtons and the mass in kilograms of (a) a 5.00-lb bag of sugar, (b) a 240-lb fullback, and \((c)\) a 1.80-ton car? (1 ton \(=2000\) lb. \()\)

Short Answer

Expert verified
Weight and Mass are: (a) Bag of Sugar: 22.2 N and 2.27 kg, (b) Fullback: 1068 N and 109 kg, (c) Car: 15972 N and 1630 kg

Step by step solution

01

Convert Pounds to Newtons for Each Item

Use the conversion factor of 4.45 newtons equals 1 pound to convert from pounds to newtons. (a) For the 5.00-lb bag of sugar, the weight will be \(5.00 \times 4.45\) N. (b) For the 240-lb fullback, the weight will be \(240 \times 4.45\) N. (c) For the 1.80-ton car, convert tons to pounds, then to newtons. As 1 ton is 2000 lb, the car weighs \( 1.80 \times 2000 \times 4.45\) N.
02

Convert Newtons to Kilograms for Each Item

Substitute the weight in newtons in the following formula to find the mass: \( \text{mass(kg)} = \text{weight(N)} / 9.8 \). (a) For the bag of sugar, the mass will now be \(5.00 \times 4.45 / 9.8\) kg. (b) For the fullback, the mass will be \(240 \times 4.45 / 9.8\) kg. (c) For the car, the mass will be \( 1.80 \times 2000 \times 4.45 / 9.8\) kg.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 77 -kg person is parachuting and experiencing a downward acceleration of \(2.5 \mathrm{~m} / \mathrm{s}^{2}\) shortly after opening the parachute. The mass of the parachute is \(5.2 \mathrm{~kg} .\) (a) Find the upward force exerted on the parachute by the air. (b) Calculate the downward force exerted by the person on the parachute.

An electron travels in a straight line from the cathode of a vacuum tube to its anode, which is \(1.5 \mathrm{~cm}\) away. It starts with zero speed and reaches the anode with a speed of \(5.8 \times\) \(10^{6} \mathrm{~m} / \mathrm{s}\). Assume constant acceleration and compute the force on the electron. This force is electrical in origin. The electron's mass is \(9.11 \times 10^{-31} \mathrm{~kg}\).

Workers are loading equipment into a freight elevator at the top floor of a building. However, they overload the elevator and the worn cable snaps. The mass of the loaded elevator at the time of the accident is \(1600 \mathrm{~kg}\). As the elevator falls, the guide rails exert a constant retarding force of \(3700 \mathrm{~N}\) on the elevator. At what speed does the elevator hit the bottom of the shaft \(72 \mathrm{~m}\) below?

The Sun yacht Diana, designed to navigate in the solar system using the pressure of sunlight, has a sail area of \(3.1 \mathrm{~km}^{2}\) and a mass of \(930 \mathrm{~kg}\). Near Earth's orbit, the Sun could exert a radiation force of \(29 \mathrm{~N}\) on its sail. (a) What acceleration would such a force impart to the craft? (b) A small acceleration can produce large effects if it acts steadily for a long enough time. Starting from rest then, how far would the craft have moved after 1 day under these conditions? ( \(c\) ) What would then be its speed? (See "The Wind from the Sun," a fascinating science fiction account by Arthur C. Clarke of a Sun yacht race.)

A car moving initially at a speed of \(50 \mathrm{mi} / \mathrm{h}(\approx 80 \mathrm{~km} / \mathrm{h})\) and weighing \(3000 \mathrm{lb}(\approx 13,000 \mathrm{~N})\) is brought to a stop in a distance of \(200 \mathrm{ft}(\approx 61 \mathrm{~m})\). Find \((a)\) the braking force and \((b)\) the time required to stop. Assuming the same braking force, find \((c)\) the distance and \((d)\) the time required to stop if the car were going \(25 \mathrm{mi} / \mathrm{h}(\approx 40 \mathrm{~km} / \mathrm{h})\) initially.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free