In a modified tug-of-war game, two people pull in opposite directions, not on a rope, but on a \(25-\mathrm{kg}\) sled resting on an icy road. If the participants exert forces of \(90 \mathrm{~N}\) and \(92 \mathrm{~N}\), what is the acceleration of the sled?

Short Answer

Expert verified
The acceleration of the sled is \(0.08 \mathrm{~m/s}^2\).

Step by step solution

01

Identify the given forces

Identify the forces exerted by the two participants. In this case, one force is \(90 \mathrm{~N}\) and the other is \(92 \mathrm{~N}\).
02

Calculate the net force

Subtract the smaller force from the larger one to get the net force. In this case, net force \( F = 92 \mathrm{~N} - 90 \mathrm{~N} = 2 \mathrm{~N}\).
03

Identify the mass of the sled

Identify the mass of the sled, which in this case is \(25 \mathrm{~kg}\).
04

Apply Newton's second law of motion

Use the formula for Newton's second law of motion, which states that acceleration = force / mass. In this case, acceleration (\(a\)) = \(2 \mathrm{~N}/25 \mathrm{~kg}\).
05

Compute the acceleration

Compute the acceleration by dividing the net force by the mass. We get acceleration (\(a\)) = \(2 \mathrm{~N}/25 \mathrm{~kg} = 0.08 \mathrm{~m/s}^2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Net Force Calculation
Understanding the net force calculation is crucial in solving problems related to Newton's second law of motion. The net force is the vector sum of all the forces acting on an object. When several forces are acting on an object in different directions, you must calculate the resultant force that will cause the object to move or change its motion.

To calculate the net force, one should take into account both the magnitude and the direction of each individual force. If two forces are acting in opposite directions, as in a tug-of-war, you subtract the smaller force from the larger one to find the net force. For example, if there are forces of 90 N and 92 N acting on a sled in opposite directions, the net force exerted on the sled is the difference between these two forces, which is 92 N - 90 N = 2 N. This net force is what will create an acceleration in the object.
Force and Acceleration
The concept of force and acceleration is a cornerstone in understanding mechanics. According to Newton's second law, the acceleration of an object is directly proportional to the net force acting on it, and inversely proportional to its mass, often expressed as the formula: \( a = \frac{F}{m} \), where \( a \) is the acceleration, \( F \) is the net force, and \( m \) is the mass of the object.

In our sled example, with a net force of 2 N acting upon a 25 kg sled, we use this law to find how quickly the sled will accelerate. Substituting the known values into the formula gives us \( a = \frac{2N}{25kg} \), which after calculation shows the sled will accelerate at 0.08 meters per second squared. It’s important to consider the direction as well; the sled will accelerate in the direction of the net force.
Mass and Acceleration
The relationship between mass and acceleration is an integral part of Newton's second law. While acceleration is a measure of how quickly an object's velocity changes, mass is a measure of the amount of matter in an object. The larger the mass of an object, the more force it takes to change its motion, hence the less acceleration it will have for a given force.

In the scenario provided, the 25 kg sled requires a certain amount of force to change its state of motion. When only a small net force is applied (2 N in this case), the resulting acceleration is small as well, resulting in a gentle increase in the sled's speed. If the sled had less mass or if the net force was greater, the acceleration would be higher. This illustrates how mass and acceleration are inversely related; as one goes up, the other must go down, assuming the net force remains constant.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A space traveler whose mass is \(75.0 \mathrm{~kg}\) leaves Earth. Compute his weight \((a)\) on Earth, \((b)\) on Mars, where \(g=3.72\) \(\mathrm{m} / \mathrm{s}^{2}\), and \((c)\) in interplanetary space. \((d)\) What is his mass at each of these locations?

Two blocks, with masses \(m_{1}=4.6 \mathrm{~kg}\) and \(m_{2}=3.8 \mathrm{~kg}\), are connected by a light spring on a horizontal frictionless table. At a certain instant, when \(m_{2}\) has an acceleration \(a_{2}=\) \(2.6 \mathrm{~m} / \mathrm{s}^{2},(a)\) what is the force on \(m_{2}\) and \((b)\) what is the acceleration of \(m_{1}\) ?

A man of mass \(83 \mathrm{~kg}\) (weight \(180 \mathrm{lb}\) ) jumps down to a concrete patio from a window ledge only \(0.48 \mathrm{~m}(=1.6 \mathrm{ft})\) above the ground. He neglects to bend his knees on landing, so that his motion is arrested in a distance of about \(2.2 \mathrm{~cm}(=0.87\) in.). ( \(a\) ) What is the average acceleration of the man from the time his feet first touch the patio to the time he is brought fully to rest? ( \(b\) ) With what average force does this jump jar his bone structure?

A car traveling at \(53 \mathrm{~km} / \mathrm{h}\) hits a bridge abutment. A passenger in the car moves forward a distance of \(65 \mathrm{~cm}\) (with respect to the road) while being brought to rest by an inflated air bag. What force (assumed constant) acts on the passenger's upper torso, which has a mass of \(39 \mathrm{~kg}\) ?

A certain particle has a weight of \(26.0 \mathrm{~N}\) at a point where the acceleration due to gravity is \(9.80 \mathrm{~m} / \mathrm{s}^{2} .(a)\) What are the weight and mass of the particle at a point where the acceleration due to gravity is \(4.60 \mathrm{~m} / \mathrm{s}^{2} ?(b)\) What are the weight and mass of the particle if it is moved to a point in space where the gravitational force is zero?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free