The bumper of a new car is being tested. The \(2300-\mathrm{kg}\) vehicle, moving at \(15 \mathrm{~m} / \mathrm{s}\), is allowed to collide with a bridge abutment, being brought to rest in a time of \(0.54 \mathrm{~s}\). Find the average force that acted on the car during impact.

Short Answer

Expert verified
The average force that acted on the car during the impact is -63894 N.

Step by step solution

01

Identify given values

The mass of the vehicle (\(m\)) is given as 2300 kg. The initial speed of the vehicle (\(v_i\)) is given as 15 m/s. The final speed of the vehicle (\(v_f\)) is 0 m/s, since it is brought to rest. The time (\(t\)) during which the car is brought to rest is given as 0.54 seconds.
02

Calculate the acceleration

The acceleration (\(a\)) can be calculated using the formula for acceleration, which is: \(a = \frac{{v_f - v_i}}{t}\). By substituting the given values into this equation, the acceleration can be calculated as \(a = \frac{{0 - 15}}{0.54} = -27.78 \, \mathrm{m/s^2}\). Negative sign indicates deceleration.
03

Calculate the force

The average force (\(F\)) that acted on the car during impact can be calculated using Newton's second law: \(F = m \cdot a\). Substituting the values of mass and acceleration into the equation, we get the force as \(F = 2300 \cdot -27.78 = -63894 \, \mathrm{N}\). The negative sign indicates that the force acted in the opposite direction to the car's initial motion.

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