Each of three helicopter rotor blades shown in Fig. 9-42 is \(5.20 \mathrm{~m}\) long and has a mass of \(240 \mathrm{~kg}\). The rotor is rotating at 350 rev/min. What is the rotational inertia of the rotor assembly about the axis of rotation? (Each blade can be considered a thin rod.)

Short Answer

Expert verified
The rotational inertia of the rotor assembly about the axis of rotation is \(I = 3 \times \frac{1}{3} \times 240 \mathrm{~kg} \times (5.20 \mathrm{~m})^2 = 8192 \mathrm{~kg} \cdot \mathrm{m}^2\).

Step by step solution

01

Find the Rotational Inertia of One Blade

Start off by calculating the rotational inertia of a single blade (as if it were a thin rod) using the formula \(I = \frac{1}{3} m L^2\). Substitute \(m = 240 \mathrm{~kg}\) and \(L = 5.20 \mathrm{~m}\) into the formula and solve.
02

Calculate Total Rotational Inertia

As the rotor assembly is made up of three blades, multiply the calculated rotational inertia of a single blade by three to find the total rotational inertia of the assembly.

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