A thin spherical shell has a radius of \(1.88 \mathrm{~m}\). An applied torque of \(960 \mathrm{~N} \cdot \mathrm{m}\) imparts an angular acceleration equal to \(6.23 \mathrm{rad} / \mathrm{s}^{2}\) about an axis through the center of the shell. Calculate \((a)\) the rotational inertia of the shell about the axis of rotation and \((b)\) the mass of the shell.

Short Answer

Expert verified
The rotational inertia of the shell is \( I = \tau / \alpha \) and the mass of the shell is \( m = I / (2/3 * r^2) \).

Step by step solution

01

Find the Rotational Inertia

Using the formula for rotational inertia \( I = \tau / \alpha \), insert the provided values: \( I = 960 \mathrm{~N} \cdot \mathrm{m} / 6.23 \mathrm{rad} / \mathrm{s}^{2}\). Calculate the solution to find \( I \).
02

Calculate the Mass

Rearrange the formula \( I = 2/3 m * r^2 \) to solve for \( m \), giving \( m = I / (2/3 * r^2) \). Insert the known values of \( I \) and \( r \) to calculate the mass.

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