Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 55

When 20 drops of water is added to a graduated cylindrical container filled with water, the level of the liquid rises from \(10 \mathrm{ml}\) to \(20 \mathrm{ml}\). Calculate the mass of each water drop.

Short Answer

Expert verified
Answer: The mass of each water drop is 0.5 g.

Step by step solution

01

Find the change in the volume of water in the cylinder

To find the change in volume, subtract the initial volume from the final volume after adding the 20 water drops. In this case, the change in the volume of water is \(20 \mathrm{ml}\) (final volume) - \(10 \mathrm{ml}\) (initial volume) which equals \(10 \mathrm{ml}\).
02

Calculate the volume of each water drop

We know there are 20 water drops added. To find the volume of each water drop, we will divide the change in volume by the number of water drops. So the volume of each water drop is \(\frac{10 \mathrm{ml}}{20 \text{ drops}} = 0.5 \mathrm{ml/drop}\).
03

Convert milliliters to cubic centimeters

The density of water is usually given in \(\mathrm{g/cm^3}\), so we need to convert the volume of each drop from milliliters to cubic centimeters. We can use the conversion factor that \(1 \mathrm{ml} = 1 \mathrm{cm^3}\). Therefore, the volume of each drop in cubic centimeters is \(0.5 \mathrm{ml} * 1 \frac{\mathrm{cm^3}}{\mathrm{ml}} = 0.5 \mathrm{cm^3}\).
04

Use the density of water to calculate the mass of each water drop

The density of water is \(1 \mathrm{g/cm^3}\) at room temperature. We can use the density formula to calculate the mass of each drop: \(density = \frac{mass}{volume}\). Rearranging to solve for mass: \(mass = density \times volume\). Substituting the values: \(mass = 1 \frac{\mathrm{g}}{\mathrm{cm^3}} \times 0.5 \mathrm{cm^3}\), we get \(mass = 0.5 \mathrm{g}\). So, the mass of each water drop is \(0.5\,\mathrm{g}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is systematization?

Write CGS unit and SI unit for given following physical quantities: (a) Area (b) Volume (c) Density (d) Velocity or Speed (e) Acceleration (f) Force (g) Weight (h) Pressure (i) Temperature (j) Energy

The mass of a body of weight 200 gf is _____ \(\mathrm{g}\). (1) \(\quad 200\) (2) \(\quad 300\) (3) 400 (4) \(\quad 20\)

Describe how triangulation method is used to measure large distances, by taking suitable example.

\(1 \mathrm{~kg} \mathrm{~m}^{-3}=\) ________ (1) \(1000 \mathrm{~g} \mathrm{~m}^{-3}\) (2) \(\frac{1}{1000} \mathrm{~g} \mathrm{~cm}^{-3}\) (3) \(10000 \mathrm{~kg} \mathrm{~cm}^{-3}\) (4) \(1 \mathrm{~g} \mathrm{~cm}^{-3}\)
See all solutions

Recommended explanations on Physics Textbooks

Waves Physics

Read Explanation

Fields in Physics

Read Explanation

Astrophysics

Read Explanation

Scientific Method Physics

Read Explanation

Mechanics and Materials

Read Explanation

Modern Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free