Chapter 2: Problem 74
Explain in detail about the different kinds of motion.
Chapter 2: Problem 74
Explain in detail about the different kinds of motion.
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Get started for freeWhen pendulum 'A' completes 20 oscillations, pendulum 'B' completes 30 oscillations. What is the ratio of their time periods?
What is meant by average speed? How is it calculated?
The distance between two stations is \(20 \mathrm{~km}\). If a train moves with a constant speed of \(60 \mathrm{~km} \mathrm{~h}^{-1}\), then the time taken by the train to reach the next station is (1) 2 hour (2) 20 minute (3) 20 second (4) 40 minute
Two hour is equal to __ seconds.
A simple pendulum was given to a physics student to determine its time period. Arrange the following steps in sequential order to determine its time period. (a) Calculate the radius of the bob ' \(R\) ' by dividing the diameter by 2 . (b) Take a metre scale and measure the length of the string from the point of suspension to the lower tip of the bob \((\ell)\). (c) Place the bob over a meter scale and hold it in position with two wooden blocks or stiff cardboards. Measure the diameter (D) of the bob. (d) Now, the length of the pendulum ( \(\ell\) ) is given by \(\left(\ell_{1}-\mathrm{R}\right)\). (e) Consider the formula \(\mathrm{T}=2 \pi . \sqrt{\frac{\ell}{g}}\) Calculate the time period of the simple pendulum. (1) abcde (2) edcba (3) bcade (4) deabc
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