The number of oscillations completed in one second is called its frequency. The bob is oscillating once in every 6 seconds The number of oscillations in \(1 \mathrm{~s}=1 / 6\)

Short Answer

Expert verified
Answer: The frequency of the bob's oscillations is 1/6 Hz.

Step by step solution

01

Understand the concept of frequency

Frequency is the number of oscillations completed in one second. It is typically measured in Hertz (Hz).
02

Write the proportion

We are given that the bob oscillates once in 6 seconds. We can represent the number of oscillations in 1 second by setting up a proportion: 1 oscillation / 6 seconds = \(f\) oscillations / 1 second, where \(f\) is the frequency we want to find.
03

Solve for the frequency

To solve for the frequency, \(f\), we can cross-multiply and divide: 1 oscillation * 1 second = \(f\) oscillations * 6 seconds This gives us: 1 = \(6f\) Now, divide by 6: \(f\) = \(\frac{1}{6}\) Hz So, the frequency of the bob's oscillations is \(\frac{1}{6}\) Hz.

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