Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 3: Problem 35

The maximum displacement of the vibrating particle is called amplitude. S.I unit is \(\mathrm{m}\). The number of vibrations per second is frequency. SI unit is hertz (Hz).

Short Answer

Expert verified
Question: Define the terms amplitude and frequency, mention their SI units, and explain their relationship in the context of a vibrating particle. Answer: Amplitude is the maximum displacement of a vibrating particle from its equilibrium position, measured in meters (m). Frequency is the measure of how often a particle oscillates or vibrates per second, measured in hertz (Hz). In the context of a vibrating particle, the amplitude provides information about the energy of the oscillation, while the frequency indicates the rate of oscillation. Both amplitude and frequency play essential roles in understanding and predicting the behavior of vibrating particles.

Step by step solution

01

Define Amplitude

Amplitude is the maximum displacement of a vibrating particle from its equilibrium position. It represents the maximum distance that the particle moves from its resting position during oscillation. The amplitude can provide information about the energy of the oscillation, as larger amplitudes generally indicate higher energy levels.
02

Mention the SI Unit of Amplitude

The SI unit of amplitude is the meter (m), which represents the length of the maximum displacement in this context.
03

Define Frequency

Frequency is the measure of how frequently a particle oscillates or vibrates. In other words, it counts the number of times per second that a vibrating particle completes a full cycle of oscillation. Frequency can provide information about the rate of oscillation and is a crucial parameter in many real-world applications such as sound and signal processing.
04

Mention the SI Unit of Frequency

The SI unit of frequency is hertz (Hz), which represents the number of oscillations or vibrations per second. One hertz (1 Hz) means that a particle is oscillating once per second.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An object moves to and fro produces oscillatory motion. If the object moves to and fro at faster rate, it is called vibratory motion.

The rest and motion are relative. An object at rest with respect to one observer may not be at rest with respect to another observer. The same can be said about motion. For a person inside a bus, the fellow passengers are at rest but the same passengers are in motion with respect to a person standing on the ground.

To mark a point for set of values \((1,5)\), look for 1 s on X-axis. Draw a line parallel to Y-axis and passing through this point. Look for \(5 \mathrm{~m}\) on the Y-axis and draw a line parallel to the X-axis passing through this point. The point of intersection gives the point that represents \((1,5) .\) In the same way, the points for other set of values can be plotted, as shown in the figure. (i) Join all the points. It is a straight line. The straight line is the distance-time graph for the motion of the motorbike. (ii) The distance-time graph of a body moving with a constant speed is a straight line. However, if the body does not move with constant speed, then its distance-time graph cannot be a straight line.

(a) Let the distance travelled be 'd'. The speed of \(^{\prime} A^{\prime}, v_{A}=\frac{d}{20} m s^{-1}\) The speed of ' \(\mathrm{B}^{\prime}, \mathrm{v}_{\mathrm{B}}=\frac{\mathrm{d}}{22} \mathrm{~m} \mathrm{~s}^{-1}\). \(\Rightarrow \frac{\mathrm{v}_{\mathrm{A}}}{\mathrm{v}_{\mathrm{B}}}=\frac{\frac{\mathrm{d}}{20}}{\frac{\mathrm{d}}{22}}=\frac{22}{20}=\frac{11}{10}=11: 10\) (b) Let them run for 't's. Then, \(\mathrm{d}_{\mathrm{A}}=\mathrm{v}_{\mathrm{A}} \times \mathrm{t}=\frac{\mathrm{d}}{20} \times \mathrm{t}\) \(\mathrm{d}_{\mathrm{B}}=\mathrm{v}_{\mathrm{B}} \times \mathrm{t}=\frac{\mathrm{d}}{22} \times \mathrm{t}\) \(\Rightarrow \frac{\mathrm{d}_{\mathrm{A}}}{\mathrm{d}_{\mathrm{B}}}=\frac{\frac{\mathrm{d}}{20}(\mathrm{t})}{\frac{\mathrm{d}}{22}(\mathrm{t})}=\frac{22}{20}=\frac{11}{10}=11: 10\)

\(\mathrm{A} \rightarrow \mathrm{f} \quad\) Spinning top rotates about its own axis. \(\mathrm{B} \rightarrow \mathrm{g} \quad\) Coin moves in a straight path over a carrom board. \(\mathrm{C} \rightarrow \mathrm{a} \quad\) A vehicle moving on a fly-over bridge undergoes curvilinear motion. \(\mathrm{D} \rightarrow \mathrm{e} \quad\) We know, a \(=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}} \Rightarrow \mathrm{t}=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{a}}\) \(\mathrm{E} \rightarrow \mathrm{c} \quad\) Distance-time graph of a body moving with constant speed is a straight line. \(\mathrm{F} \rightarrow \mathrm{b} \quad\) One oscillation means one to-and-for motion of a body. \(\mathrm{G} \rightarrow \mathrm{d} \quad\) The length of a seconds pendulum is \(100 \mathrm{~cm}\) (or) \(1 \mathrm{~m} .\)
See all solutions

Recommended explanations on Physics Textbooks

Modern Physics

Read Explanation

Fluids

Read Explanation

Radiation

Read Explanation

Mechanics and Materials

Read Explanation

Work Energy and Power

Read Explanation

Physical Quantities And Units

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free