Fill in the Blanks. length \(\mathrm{T} \alpha \sqrt{\ell}\) Time period of a simple pendulum depends on its length.

Short Answer

Expert verified
Answer: The missing elements in the given equation are the constant 2 * 𝜋 and the denominator with the acceleration due to gravity 'g.' The completed equation should be 𝑇 = 2𝜋√(𝑙/g).

Step by step solution

01

Recall the formula for the time period of a simple pendulum

To find the time period of a simple pendulum, we need to recall the formula: T = 2 * \(\pi\) * \(\sqrt{\frac{l}{g}}\), where T is the time period, l is the length of the pendulum, and g is the acceleration due to gravity.
02

Identify the missing information in the given equation

The given equation for the time period of a simple pendulum is: \(\mathrm{T} \alpha \sqrt{\ell}\). We notice that the constant 2 * \(\pi\) and the denominator with the acceleration due to gravity 'g' are missing from the equation.
03

Fill in the missing information

We need to introduce the constant 2 * \(\pi\) and the denominator containing acceleration due to gravity, 'g.' So, the missing information is 2 * \(\pi\) and 'g.' The completed equation should be: \(\mathrm{T} \alpha 2\pi\sqrt{\frac{\ell}{g}}\).
04

Rewrite the equation with the proportional constant

The given equation is written in proportionality form (α). To make it an equality, we can rewrite it with a proportional constant as: \(\mathrm{T} = k\sqrt{\frac{\ell}{g}}\), where 'k' is the constant of proportionality. In this specific case, the constant of proportionality is 2 * \(\pi\), so the complete equation is: \(\mathrm{T} = 2\pi\sqrt{\frac{\ell}{g}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Pendulum Formula
Understanding the time period of a simple pendulum is crucial for students tackling physics problems. The time period, denoted by T, is the time it takes for one complete cycle of the pendulum's swing. The formula for the time period of a simple pendulum is given by:
\[ T = 2\pi\sqrt{\frac{l}{g}} \]
where T represents the time period, l is the length of the pendulum, and g is the acceleration due to gravity. This formula is derived from the basic principles of harmonic motion and showcases a direct relationship between the length of the pendilum and the time period, which is modulated by the acceleration due to gravity operating on the pendulum.

To solidify your understanding, it is important to remember that only the length of the pendulum and the acceleration due to gravity affect the time period, not the mass attached to the pendulum or the amplitude of the swing, as long as it's not too large. The formula shows a simple yet profound relationship at the heart of pendular motion that has applications ranging from clocks to seismology.
Proportionality in Physics
Proportionality is a foundational concept in physics that expresses how two quantities change in relation to each other. It's often shown using the symbol \( \alpha \), which means 'is proportional to.' In the context of the simple pendulum, the time period T is proportional to the square root of the length of the pendulum, as shown in the statement:
\[ T \alpha \sqrt{l} \]
This implies that if you were to increase the length of the pendulum, the time period would increase following a specific mathematical relation, which involves taking the square root of the length. It's this proportionality that helps physicists and engineers predict the behavior of systems under different conditions. When solving problems in physics, identifying the proportional relationships helps simplify complex equations and understand the system's dynamics more clearly.

However, it's necessary to convert the proportionality to an equation to make actual calculations. This is done by introducing a constant that balances the equation, and for the simple pendulum's time period, that constant is \(2\pi\), derived from the pendulum's circular motion. Once the constant is established, you'll have a full-fledged formula that can quantify the period of oscillation.
Acceleration Due to Gravity
In the realm of pendulums and many other physics problems, the acceleration due to gravity (often represented by \(g\)) is a critical factor. On the surface of Earth, this acceleration is approximately \(9.81 m/s^2\), though it slightly varies depending on the altitude and latitude. It is the force that pulls the pendulum downward as it swings, ultimately dictating the speed of the oscillation along with the length of the string.

The reason the acceleration due to gravity appears in the denominator of the time period formula for a simple pendulum is because it inversely affects the period. As gravity's pull gets stronger (with an increase in \(g\)), the time it takes for one complete oscillation becomes shorter, and vice versa. This relationship is vital, especially in experimental settings where local gravitational variations can impact precise measurements — such as in gravimetry. Understanding how gravity interplays with pendular motion is fundamental not just for classroom exercises but also for real-world engineering and scientific applications.

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Most popular questions from this chapter

Speed \(=\frac{\text { distance }}{\text { time }}\) Time \(=\frac{\text { distance }}{\text { speed }}=\frac{20 \mathrm{~km}}{60 \mathrm{~km} \mathrm{~h}^{-1}}=\frac{1}{3} \mathrm{~h}\) \(=\frac{1}{3} \times 60=20\) minutes

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The rest and motion are relative. An object at rest with respect to one observer may not be at rest with respect to another observer. The same can be said about motion. For a person inside a bus, the fellow passengers are at rest but the same passengers are in motion with respect to a person standing on the ground.

The different kinds of motion are: (i) Translatory motion: \(\mathrm{A}\) bus moving on a road, the motion of a rising balloon, the free fall of a stone under gravity, the motion of a cricket ball when it is hit by a batsman are examples of translatory motion. Translatory motion is further classified as rectilinear motion and curvilinear motion. When an object moves along a straight path, its motion is said to be rectilinear motion. The marching of soldiers on a straight road, the motion of a car on a straight road, the motion of carrom board coin are examples of rectilinear motion. When an object moves along curved path, its motion is called curvilinear motion. A bus moving on a fly-over bridge, a car taking a turn, a football kicked from the ground into air all have curvilinear motion. (ii) Rotatory motion: In this type of motion, the object rotates about a fixed axis. The motion of blades of a ceiling fan, the spin motion of a top, the motion of turbine, the motion of the earth around the sun are all circular or rotatory motion. In some cases, the rotatory and translatory motions take place simultaneously. When a bicycle moves, its wheels undergo translatory and rotatory motion. (iii) Oscillatory motion: A boy on a swing moves to-and-fro (back and forth). The motion such as above, where an object moves to-and-fro is called oscillatory motion. Other examples of oscillatory motion are the motion of the pendulum of a clock, the motion of a needle of a sewing machine, the motion of a piston of an engine etc.

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