The rest and motion are relative. An object at rest with respect to one observer may not be at rest with respect to another observer. The same can be said about motion. For a person inside a bus, the fellow passengers are at rest but the same passengers are in motion with respect to a person standing on the ground.

Short Answer

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Question: Explain the concept of relative rest and motion using the example of passengers inside a bus as observed by someone inside the bus and someone standing on the ground. Answer: Relative rest and motion refer to an object's change in position as observed from different perspectives. In the example of passengers inside a bus, they appear to be at rest relative to an observer inside the bus as their positions do not change with respect to each other. However, from the perspective of someone standing on the ground, the passengers are in motion as their positions change relative to the observer as the bus moves. This demonstrates that rest and motion are relative concepts depending on the observer's point of view.

Step by step solution

01

Understand the terms rest and motion

Rest refers to an object not changing its position with respect to its surroundings, whereas motion means the object is changing its position. Both of these terms are relative, meaning they depend on the observer's point of view.
02

Analyze the situation from the perspective of an observer inside the bus

From the point of view of a person sitting inside the bus, the other passengers also inside the bus appear to be at rest. This is because they are all moving with the same velocity as the bus, so their positions with respect to each other are not changing.
03

Analyze the situation from the perspective of an observer outside the bus

Now, consider an observer standing on the ground, watching the bus go by. From his perspective, the passengers inside the bus are in motion. This is because as the bus moves, the passengers' positions with respect to the person standing on the ground are changing.
04

Relate the concept of relative rest and motion to the given example

The example of passengers inside a bus demonstrates that rest and motion are relative concepts. An object (in this case, the passengers) can appear to be at rest with respect to one observer (the person inside the bus) but in motion with respect to another observer (the person standing on the ground).

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Most popular questions from this chapter

\(\mathrm{A} \rightarrow \mathrm{b} \quad\) The piston of a motorcar engine moving at uniform speed is said to be in periodic motion. \(\mathrm{B} \rightarrow \mathrm{e}, \mathrm{b} \quad\) The objects executing vibratory motion undergo change in shape or size. The piston of a motor car engine executes vibratory motion. \(\mathrm{C} \rightarrow \mathrm{g} \quad\) Body at rest will have zero speed as well as zero velocity. \(\mathrm{D} \rightarrow\) a Maximum displacement of a body from its mean position is called amplitude. \(\mathrm{E} \rightarrow \mathrm{c} \quad\) A body moving with variable speed is said to be in non-uniform motion. \(\mathrm{F} \rightarrow \mathrm{d} \quad 1 \mathrm{~ms}^{-1}=\frac{1 \mathrm{~m}}{1 \mathrm{~s}}=\frac{\frac{1}{100} \mathrm{~km}}{\frac{1}{3600} \mathrm{~h}}=\frac{18}{5} \mathrm{~km} \mathrm{~h}^{-1}\) \(\mathrm{G} \rightarrow \mathrm{f} \quad\) Average velocity \(=\frac{\text { Total displacement }}{\text { Total time }}\)

Fill in the Blanks. \(\frac{1}{1000}\) 1000 millisecond \(=1 \mathrm{~s}\) \(\Rightarrow 1\) millisecond \(=\frac{1}{1000}\) th part of a second.

Fill in the Blanks. \(7200 \mathrm{~s}\) 2 hour \(=2 \times 60\) minutes \(=2 \times 60 \times 60 \mathrm{~s}=7200 \mathrm{~s}\)

(i) When a body travels in straight line path, its distance and displacements are equal and hence in a given time, velocity is equal to speed. (ii) Average velocity of a body may be equal to zero if the total displacement of is body is equal to zero, but average speed will not be equal to zero unless and until distance covered is zero (i.e., body at rest). (iii) To describe the velocity, direction is necessary as velocity is speed in a specific direction.

Speed \(=\frac{\text { distance }}{\text { time }}\) Time \(=\frac{\text { distance }}{\text { speed }}=\frac{20 \mathrm{~km}}{60 \mathrm{~km} \mathrm{~h}^{-1}}=\frac{1}{3} \mathrm{~h}\) \(=\frac{1}{3} \times 60=20\) minutes

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