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Chapter 3: Problem 7

Fill in the Blanks. uniform The body moves with uniform velocity of u \(\mathrm{m} \mathrm{s}^{-1}\) towards east direction.

Short Answer

Expert verified
Answer: It means that the body is moving at a constant speed of u meters per second in a straight line towards the east direction without any changes in speed or direction.

Step by step solution

01

Understanding uniform velocity

Uniform velocity means an object is moving at a constant speed in a straight line. In this case, the body is moving with a uniform velocity of u m/s.
02

Identifying the direction

The body is moving towards the east. In the context of this statement, the direction is given in terms of cardinal points (north, south, east, and west).
03

Completed Sentence

The body moves with uniform velocity of u m/s towards the east direction.

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Most popular questions from this chapter

We know, \(\mathrm{T}=2 \pi \sqrt{\frac{l}{\mathrm{~g}}}\) The time period of seconds pendulum, \(\mathrm{T}_{1}=2 \mathrm{~s}\) The length of the second pendulum \(\ell_{1}=100 \mathrm{~cm}=1 \mathrm{~m}\) Now, the new length of the pendulum \(\ell_{2}=2 \ell_{1}\) \(\Rightarrow \ell_{2}=200 \mathrm{~cm}=2 \mathrm{~m}\) Let the new time period of the pendulum be \(=\mathrm{T}_{2}\) \(\Rightarrow \mathrm{T} \alpha \sqrt{l}\) \(\Rightarrow \frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\sqrt{\frac{l_{1}}{l_{2}}} \Rightarrow \mathrm{T}_{2}=\mathrm{T}_{1} \sqrt{\frac{l_{2}}{l_{1}}}\) \(\mathrm{T}_{2}=2 \times \sqrt{\frac{2 l_{1}}{l_{1}}}=2 \sqrt{2} \mathrm{~s}\) The time period becomes \(2 \sqrt{2}\) times the original one.

The maximum displacement of the vibrating particle is called amplitude. S.I unit is \(\mathrm{m}\). The number of vibrations per second is frequency. SI unit is hertz (Hz).

A simple pendulum that has time period of \(2 \mathrm{~s}\) is called seconds pendulum. Its length is approximately \(100 \mathrm{~cm}\) or \(1 \mathrm{~m} .\)

The average distance per unit time, when the body is moving with variable speed, is called average speed, Average speed \(=\frac{\text { Total distance travelled }}{\text { Total time taken }}\)

Fill in the Blanks. \(\frac{1}{1000}\) 1000 millisecond \(=1 \mathrm{~s}\) \(\Rightarrow 1\) millisecond \(=\frac{1}{1000}\) th part of a second.
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