A light ray is incident on a plane mirror placed in a horizontal plane, making an angle of \(30^{\circ}\) with the vertical, then the angle between the reflected ray and the normal is ________. (1) \(35^{\circ}\) (2) \(60^{\circ}\) (3) \(90^{\circ}\) (4) \(30^{\circ}\)

Short Answer

Expert verified
Answer: The angle between the reflected ray and the normal is \(60^{\circ}\).

Step by step solution

01

Understand the Laws of Reflection

The laws of reflection state that the angle of incidence is equal to the angle of reflection, and the incident ray, the reflected ray, and the normal to the mirror all lie in the same plane.
02

Determine the Angle of Incidence

The problem states that the light ray makes an angle of \(30^{\circ}\) with the vertical. We need to find the angle between the incident ray and the normal (angle of incidence). The normal is perpendicular to the mirror, so the angle of incidence (\(\angle i\)) is the complement of the given angle. Since the sum of a vertical angle and its complement is \(90^{\circ}\), we can calculate the angle of incidence as follows: $$\angle i = 90^{\circ} - 30^{\circ} = 60^{\circ}$$
03

Apply the Laws of Reflection

Now that we have the angle of incidence, we can apply the laws of reflection. Because the angle of incidence is equal to the angle of reflection, the angle between the reflected ray and the normal (\(\angle r\)) is also equal to the angle of incidence. $$\angle r = \angle i = 60^{\circ}$$
04

Identify the correct option

From the calculation in Step 3, the angle between the reflected ray and the normal is \(60^{\circ}\). Therefore, the correct option is (2).

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