A 15°C, 2.0-cm-diameter aluminum bar just barely slips between two rigid steel walls 10.0 cm apart. If the bar is warmed to 25°C, how much force does it exert on each wall?

Short Answer

Expert verified

The accurate answer is14.5kn

Step by step solution

01

Description 

A 15°C, 2.0-cm-diameter aluminum bar just barely slips between two rigid steel walls 10.0 cm apart.

The young module depicts

p=FA=YLL

02

Finding the result 

The description provided that

F=AYLL=π4D2YLL

From the expression for linear thermal expansion is:

LL=αT

Therefore, the final expansion will be:

F=πD24YαT

The table of 18.4 depicts that the coefficient of linear thermal expansion of Aluminium is almost 23.10-51/k.

The table of 14.3 depicts that Aluminium's young modules is Y=20.1010N/m2.

Thus, F=π·0.0224·20·1010·2.3·10-5·10=14500N

Therefore, If the bar is warmed to 25°C, the force of 14.5kN, it exert on each wall.

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