The air temperature and pressure in a laboratory are 20°C and 1.0 atm. A 1.0 L container is open to the air. The container is then sealed and placed in a bath of boiling water. After reaching thermal equilibrium, the container is opened. How many moles of air escape?

Short Answer

Expert verified

Δn=0.0113molis the number of moles of air that escaped from the container.

Step by step solution

01

Given information

The temperature isT=20+273=293KT=20+273=293K

Pressure P=1atm

The thermal temperature of equilibrium T2=100+273=373K

It's vital to remember that the number of moles doesn't change while they're immersed in boiling water. When the container is opened, the pressure equals 1atm

formula used:

Ideal gas law

PV=nRT

02

Calculation

DescriptionSteps
Step:1 The number moles calculating


n=PVRT=latm(LL)293K0.082057LatmK-1mol-1n=0.0415molP, V, R are constantsn2n1=T1T2n2=273373(0.0415)n2=0.0528mol

Step:2 Counting the number of moles who have gotten away

Δn=n2-n1=0.0528mol-0.0415molΔn=0.0113mol

Δn=n2-n1=0.0528mol-0.0415molΔn=0.0113mol


Δn=0.0113is the number of moles of air that escaped from the container.

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