FIGURE Q32.1shows emf phasors a, b, and c.

a. For each, what is the instantaneous value of the emf?

b. At this instant, is the magnitude of each emf increasing, decreasing, or holding constant?

Short Answer

Expert verified

a)EMFa=-100V,EMFb=60VandEMFc=80V

b) Decreasing, Decreasing, Increasing

Step by step solution

01

Part(a) Step 1: Given information

We need to find instantaneous values of the emf in different position and explain is it increasing, decreasing or remain constant

02

Part (a) Step 2:  Explanation 

As we know that the general expression of instantaneous emf isV=Vοcos(ωt+ϕ)

Due to the phase angle, the instantaneous emf changes from the x-axis. So, to find the emf for each phasor, we take the

projection of each phasor on x axis.

we can consider each block equals 20V,

For phasor (a): The projection on x-axis is at(-100V). so for phasor, the

number of blocks is 5, therefore, the emf is

EMFa=-100V

For phasor (b): The projection on x-axis is at (+60V)So for phasor, the

number of blocks is 3, therefore, the emf is5x20V=60V.

EMFb=60V

For phasor (c): The projection on x-axis is at (+80V). so for phasor, the

number of blocks is 4, therefore, the emf is 4x20V=80V.

EMFc=80V

03

Part (b) Step 1: Given information

We have given that the figure

We need to find that EMF at different position is increasing, decreasing or remain constant

04

Part (b) Step 2: Explanation 

a: The EMF a(=-100V)is Decreasing.

b: The EMF b(=60V)is Decreasing.

c: The EMF c(=80V)is Increasing.

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