The emf phasor in FIGURE EX32.2 is shown at t=15ms.

a. What is the angular frequency ω? Assume this is the first rotation.

b. What is the instantaneous value of the emf?

Short Answer

Expert verified

The angular frequency ωis 244rad/sand instantaneous value of the emf is-10V.

Step by step solution

01

Part (a) Step 1: Given information

We are given that time t=15ms, Eo=12Vand =150(as the phasor rotates anticlockwise towards X-axis)

02

Part (a) Step 2: Calculation

As we know that-

E=E0cos(ωt+)

ωt=180+ωt=180+30ωt=210 (as phasor rotates anticlockwise)

Now converting degrees into radian

210=210πrad180=7πrad6

Now,

ωt=7πrad6ω(15×10-3)=7πrad6ω=244rad/s

03

Part (b) Step 1: Given information

We are given that-

E0=12V=150

04

Part (b) Step 2: Calculation

As we know that peak valueE0=12V will occur when ωt=0

So now in the expression,

E=E0cos(ωt+)E=12Vcos(0+150)E=-10V

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