Chapter 32: Q. 20 (page 924) URL copied to clipboard! Now share some education! A high-pass filter consists of a 1.59mFcapacitor in series with a 100Ωresistor. The circuit is driven by an ACsource with a peak voltage of 5.00V. a. What is the crossover frequency fc? b. What is VRwhen f=12fc,fc, and 2fc? Short Answer Expert verified (a) Crossover frequency , fc=1000Hz(b) Value ofVR=3.54V Step by step solution 01 AC Source The flow of electrical charge that occasionally reverses direction is understood as electricity (ac).As mentioned in Induced Electric Fields, an alternating emf generated in an exceedingly very station produces an ac.An ac circuit is one during which the ac source varies frequently, often sinusoidally. 02 Find Crossover frequency Given valuesC=1.59×10-6F(farad)R=100Ω(ohm)εo=5.00V(voltage)we use formulaw=1RCDerive from the formula,w=1RC2πfc=1RCfc=12πRClocalid="1650213173701" fc=12π×(100)Ω×1.59×10-6)Ffc=1000Hz 03 Find value of voltage VR=εoRR2+1w2C2VR=εoRR2+R2C2C2Substitute the values,VR=5.00V1.41VR=3.54Vf=fc⇒VR'=εo2 Unlock Step-by-Step Solutions & Ace Your Exams! Full Textbook Solutions Get detailed explanations and key concepts Unlimited Al creation Al flashcards, explanations, exams and more... Ads-free access To over 500 millions flashcards Money-back guarantee We refund you if you fail your exam. Start your free trial Over 30 million students worldwide already upgrade their learning with Vaia!