A capacitor is connected across an oscillating emf. The peak current through the capacitor is 2A.What is the peak current if:

a. The capacitance Cis doubled?

b. The peak emf E0is doubled?

c. The frequency vis doubled?

Short Answer

Expert verified

(a.) 2A

(b.) 4A

(c.) 2A

Step by step solution

01

Part (a) Step1: Given Information

We are given that A resistor is connected across an oscillating emf. The peak current through the Resistor is2A.

We need to find that what is the peak current if ResistanceCis doubled.

02

Part (a) Step 2: Explanation

In this we have to find what is the value of max current in circuit while changing the value of

C,v,E0

It is based on RLC circuit

We know that ,

The maximum current of RLC circuit is

I=E0R

Now we see that I is directly Proportional to E0and inversely proportional to R

So ,

If Cis doubled then Iwill be same as present value so

I=II=2A

Hence final answers is2A.

03

Part (b) Step 1: Given information

We are given that A resistor is connected across an oscillating emf. The peak current through the Resistor is 2A.

We need to find that what is the peak current if resistance E0is doubled.

04

Part (b)  Step 2 : Explanation 

In this q we have to find what is the value of max current in circuit while changing the value of

C,v,E0

It is based on RLC circuit

We know that ,

The maximum current of RLC circuit is

I=E0R

Now we see that I is directly Proportional to E0 and inversely proportional to R

So ,

If E0is doubled then Iwill be double of present value so

I=2II=4A

Hence final answers is4A

05

Part (c) Step 1: Given Information

We are given that A resistor is connected across an oscillating emf. The peak current through the Resistor is 2A.

We need to find that what is the peak current if resistance Ris doubled.

06

Part (c) Step 2 : Explanation

In this q we have to find what is the value of max current in circuit while changing the value of

C,v,E0

It is based on RLC circuit

We know that ,

The maximum current of RLC circuit is

I=E0/R

Now we see that I is directly Proportional to E0and inversely proportional to R

So ,

If vis doubled then Iwill be same as present value so

I=II=2A

Hence final answers is2A

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that Equation32.27for the phase angleϕof a seriesRLC circuit gives the correct result for a capacitor-only circuit.

An inductor has a peak current of 330μA when the peak voltage at45MHzis 2.2V

a. What is the inductance?

b. If the peak voltage is held constant, what is the peak current at 90MHz?

In the series RLC circuit represented by the phasors of FIGURE Q32.7, is the EMF frequency less than, equal to, or greater than the resonance frequency ω0? Explain.

A capacitor has a peak current of 330μA{"x":[[5,35,36,5,5,17,27,34,35,32,20,8,4],[45,74,75,45,46,58,69,74,73,61,49,43],[97,84,82,82,87,101,110,111,111,107,97],[152,165,166,180],[158,174],[128.5,128.5,128.5,127.5,126.5,125.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,124.5,123.5,123.5,123.5,123.5,123.5,123.5,123.5,122.5,122.5,122.5,121.5,121.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,120.5,121.5,121.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,122.5,123.5,124.5,124.5,124.5,125.5,126.5,127.5,128.5,128.5,128.5,128.5,129.5,130.5,130.5,131.5,132.5,132.5,132.5,133.5,133.5,134.5,134.5,135.5,135.5,135.5,135.5,136.5,136.5,136.5,137.5,137.5,137.5,138.5,138.5,138.5,138.5,138.5,138.5,138.5,138.5,137.5,136.5,136.5,136.5,136.5,136.5,136.5,136.5,136.5,136.5,136.5,136.5,136.5,135.5,135.5,135.5,135.5,136.5,136.5,136.5,137.5,137.5,137.5,137.5,138.5,139.5,139.5,140.5,140.5,140.5,141.5,142.5,143.5,143.5,144.5,144.5,144.5,144.5,144.5,144.5,145.5,145.5,145.5,146.5,146.5,146.5]],"y":[[8,8,8,50,50,50,54,64,88,111,116,113,101],[8,8,8,50,50,49,55,71,107,116,114,100],[116,110,65,29,10,8,17,64,96,113,116],[115,8,8,115],[73,73],[106.39999389648438,103.39999389648438,102.39999389648438,96.39999389648438,91.39999389648438,87.39999389648438,86.39999389648438,85.39999389648438,82.39999389648438,79.39999389648438,78.39999389648438,76.39999389648438,74.39999389648438,70.39999389648438,69.39999389648438,65.39999389648438,62.399993896484375,58.399993896484375,54.399993896484375,50.399993896484375,49.399993896484375,47.399993896484375,46.399993896484375,42.399993896484375,37.399993896484375,35.399993896484375,34.399993896484375,32.399993896484375,30.399993896484375,28.399993896484375,27.399993896484375,26.399993896484375,25.399993896484375,22.399993896484375,19.399993896484375,17.399993896484375,16.399993896484375,14.399993896484375,11.399993896484375,6.399993896484375,3.399993896484375,2.399993896484375,1.399993896484375,0.399993896484375,-0.600006103515625,0.399993896484375,2.399993896484375,3.399993896484375,5.399993896484375,6.399993896484375,7.399993896484375,9.399993896484375,10.399993896484375,10.399993896484375,13.399993896484375,16.399993896484375,17.399993896484375,18.399993896484375,22.399993896484375,24.399993896484375,27.399993896484375,29.399993896484375,30.399993896484375,32.399993896484375,34.399993896484375,36.399993896484375,38.399993896484375,41.399993896484375,42.399993896484375,46.399993896484375,46.399993896484375,47.399993896484375,48.399993896484375,50.399993896484375,53.399993896484375,54.399993896484375,54.399993896484375,55.399993896484375,57.399993896484375,58.399993896484375,59.399993896484375,61.399993896484375,63.399993896484375,64.39999389648438,65.39999389648438,66.39999389648438,66.39999389648438,67.39999389648438,70.39999389648438,71.39999389648438,72.39999389648438,72.39999389648438,70.39999389648438,70.39999389648438,69.39999389648438,67.39999389648438,66.39999389648438,65.39999389648438,64.39999389648438,63.399993896484375,62.399993896484375,62.399993896484375,61.399993896484375,60.399993896484375,59.399993896484375,58.399993896484375,58.399993896484375,57.399993896484375,56.399993896484375,54.399993896484375,54.399993896484375,53.399993896484375,51.399993896484375,50.399993896484375,48.399993896484375,42.399993896484375,33.399993896484375,27.399993896484375,25.399993896484375,24.399993896484375,23.399993896484375,24.399993896484375,25.399993896484375,26.399993896484375,26.399993896484375,26.399993896484375,27.399993896484375,28.399993896484375,29.399993896484375,30.399993896484375,30.399993896484375,31.399993896484375,32.399993896484375,34.399993896484375,37.399993896484375,38.399993896484375,39.399993896484375,40.399993896484375,41.399993896484375,42.399993896484375,42.399993896484375,44.399993896484375,45.399993896484375,46.399993896484375,46.399993896484375,47.399993896484375,49.399993896484375,50.399993896484375,51.399993896484375,54.399993896484375,54.399993896484375,54.399993896484375,55.399993896484375,56.399993896484375,57.399993896484375,59.399993896484375,62.399993896484375,63.399993896484375,64.39999389648438,65.39999389648438,67.39999389648438,68.39999389648438,69.39999389648438]],"t":[[0,0,0,0,0,0,0,0,0,0,0,0,0],[0,0,0,0,0,0,0,0,0,0,0,0],[0,0,0,0,0,0,0,0,0,0,0],[0,0,0,0],[0,0],[1650006364907,1650006365160,1650006365165,1650006365182,1650006365200,1650006365216,1650006365233,1650006365251,1650006365265,1650006365290,1650006365299,1650006365316,1650006365333,1650006365352,1650006365366,1650006365382,1650006365399,1650006365415,1650006365432,1650006365448,1650006365465,1650006365482,1650006365500,1650006365515,1650006365536,1650006365550,1650006365565,1650006365582,1650006365599,1650006365615,1650006365634,1650006365648,1650006365699,1650006365715,1650006365732,1650006365749,1650006365798,1650006365816,1650006365832,1650006365848,1650006365865,1650006365882,1650006365898,1650006365915,1650006365965,1650006366298,1650006366316,1650006366332,1650006366350,1650006366365,1650006366382,1650006366398,1650006366416,1650006366432,1650006366449,1650006366466,1650006366482,1650006366515,1650006366565,1650006366581,1650006366599,1650006366615,1650006366631,1650006366648,1650006366715,1650006366732,1650006366749,1650006366764,1650006366781,1650006366798,1650006366819,1650006366831,1650006366898,1650006366916,1650006366932,1650006366948,1650006366998,1650006367027,1650006367049,1650006367066,1650006367149,1650006367166,1650006367182,1650006367198,1650006367219,1650006367266,1650006367328,1650006367335,1650006367366,1650006367381,1650006367423,1650006367632,1650006367647,1650006367665,1650006367681,1650006367697,1650006367714,1650006367732,1650006367750,1650006367764,1650006367781,1650006367798,1650006367814,1650006367832,1650006367858,1650006367866,1650006367898,1650006367915,1650006367948,1650006367964,1650006367990,1650006368005,1650006368048,1650006368064,1650006368082,1650006368097,1650006368114,1650006368131,1650006368148,1650006368165,1650006368429,1650006368685,1650006368699,1650006368736,1650006369080,1650006369099,1650006369123,1650006369249,1650006369268,1650006369284,1650006369333,1650006369384,1650006369400,1650006369416,1650006369434,1650006369451,1650006369468,1650006369492,1650006369584,1650006369601,1650006369617,1650006369632,1650006369650,1650006369668,1650006369684,1650006369738,1650006369766,1650006369784,1650006369800,1650006369816,1650006369834,1650006369854,1650006369878,1650006369908,1650006369932,1650006369950,1650006369968,1650006369982,1650006370000,1650006370067,1650006370084,1650006370101,1650006370118]],"version":"2.0.0"}when the peak volt-age at 250kHZis 2.2V.

a. What is the capacitance?

b. If the peak voltage is held constant, what is the peak current at 500kHZ?

An inductor is connected across an oscillating emf. The peak current through the inductor is 2.0A. What is the peak current if:

a. The inductance Lis doubled?

b. The peak emf E0is doubled?

c. The frequency Vis doubled?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free