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Chapter 32: Q. 3 (page 923)

A $110 H z$ source of emf has a peak voltage of $50 V$ . Draw the emf phasor at $t = 3.0 m s$ .

Short Answer

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Required emf phasor is:

Step by step solution

Given information

We are given that Peak voltage = $50 V$ ,frequency = $110 H z$ , $t = 3 x 10^{- 3} s$

Explanation

We know that $ω = 2 π f$

$ω = 2 π \times 110 H z ω = 220 π r a d / s$

then, We need to find angle $θ$

$θ = ω t = 220 π \times 3 \times 10^{- 3} = 0.66 π θ = \frac{2}{3} π x 57.29 ° (1 r a d = 57 . 29^{\circ}) θ ≃ 120^{\circ}$

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A 110Hzsource of emf has a peak voltage of 50V. Draw the emf phasor at t=3.0ms.

Short Answer

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Given information

Explanation

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A $110 H z$ source of emf has a peak voltage of $50 V$ . Draw the emf phasor at $t = 3.0 m s$ .