Chapter 32: Q. 38 (page 925)

A series RLC circuit attached to a $120 V / 60 H z$ power line draws a $2.4 A$ rms current with a power factor of $0.87$ . What is the value of the resistor?

Short Answer

Expert verified

The value of resistor is $43.5 Ω$ .

Step by step solution

Given Information

We are given that rms current $I = 2.4 A$ ,Voltage is $V = 120 V$ and power factor is $P_{f} = 0.87$

and we have to find out the value of resistor.

Formula Used

Now, using the formula,

We get $P = (V) (I) (P_{f})$

where V is voltage, I is current and $P_{f}$ is the power factor.

Putting the value of variables in equation,

We get,

$P = (120) (2.4) (0.87) = 250.56$ W

Simplify

Now, using the formula

$P = I^{2} R$ ,

where P is power, I is current and R is resistor,

Putting all the variable in equation we get,

$250.56 = {(2.4)}^{2} R$

On solving,

we get

$R = 43.5 Ω$

The value of resistor is $43.5 Ω$ .

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A series RLC circuit attached to a $120 V / 60 H z$ power line draws a $2.4 A$ rms current with a power factor of $0.87$ . What is the value of the resistor?

Short Answer

Step by step solution

Given Information

Formula Used

Simplify

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A series RLC circuit attached to a 120V/60Hzpower line draws a 2.4Arms current with a power factor of 0.87. What is the value of the resistor?

Short Answer

Step by step solution

Given Information

Formula Used

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Fluids

Quantum Physics

Further Mechanics and Thermal Physics

Kinematics Physics

Atoms and Radioactivity

Linear Momentum

Study anywhere. Anytime. Across all devices.

A series RLC circuit attached to a $120 V / 60 H z$ power line draws a $2.4 A$ rms current with a power factor of $0.87$ . What is the value of the resistor?