A low-pass RC filter has a crossover frequency f_c=200 Hz.What is f_c if:

a. The resistance R is doubled?

b. The capacitance C is doubled?

c. The peak emf E0 is doubled?

we have given that

A low-pass RC filter has a crossover frequency f_c =200 Hz

we have to find $f_c$ if resistance R is doubled

as we know in low- pass R C filter,

$f_c=\frac{1}{2\pi RC}$

according to given question

$f_c=\frac{1}{2\pi RC}=200$Hz

if resistance R is doubled

${\left(f_c\right)}^{\text{'}}=\frac{1}{2\pi \left(2R\right)C}=\frac{f_c}{2}=\frac{200}{2}=100$Hz

we have given that

A low-pass RC filter has a crossover frequency f_c=200 Hz

we have to find $f_c$if capacitance C is doubled

as we know in low- pass R C filter,

$f_c=\frac{1}{2\pi RC}$

according to given question

$f_c=\frac{1}{2\pi RC}=200$Hz

if capacitance C is doubled

${\left(f_c\right)}^{\text{'}}=\frac{1}{2\pi R\left(2C\right)}=\frac{f_c}{2}=\frac{200}{2}=100$Hz

we have given that

A low-pass RC filter has a crossover frequency f_c=200 Hz

we have to find $f_c$ if peak voltage E₀ is doubled

as we know in low- pass R C filter,

$f_c=\frac{1}{2\pi RC}$

according to given question

$f_c=\frac{1}{2\pi RC}=200$Hz

if peak emf E₀ is doubled there will be no change therefore,

$f_c=200$Hz