The small transformers that power many consumer products produce a12.0Vrms, 60Hzemf. Design a circuit using resistors and capacitors that uses the transformer voltage as an input and produces a 6.0Vrms output that leads the input voltage by 45°.

Short Answer

Expert verified

TheR1=6Ω,R2=2.5ΩandC=3.12×10-4F.

Step by step solution

01

Step 1:Given Information 

We are given that small transformer produces voltage 12Vrms,60Hzemf.

We have to design the circuit which have 6Vrmsoutput that leads the input voltage by45°.

02

Step 2:Formula Used

As the capacitor voltage is lead by the resistor voltage . So, the input must ne in between the resistors and the phase difference is of 45°.

Now, ZR=ZC

then VC=VR=122

which givesVC=VR=8.5V.

03

Step 3:Simlify

Let R1be the resistor needed to make the voltage 6Vrms

then R16=ZR8.5

On simplifying we get,

R1=0.71ZR

let role="math" localid="1650018615730" ZR=8.5Ωthen

On solving, R1=6ΩandR2=2.5Ω

and ZC=8.5Ω=1ωC

where ω=2π×60

On solving we get,

C=3.12×10-3F

Hence, the resistorR1=6ΩandR2=2.5Ωand the capacitorC=3.12×10-3F.

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