In FIGURE, what is the current supplied by the emf when

(a) the frequency is very small and

(b) the frequency is very large

We are given that the values of

$\begin{array}{l}{R}_1=100\Omega \\ R_2=50\Omega \\ {\epsilon }_o=10V\end{array}$

And We have to find the current supplied by emf when the frequency is very small .

When the frequency is very small then the branch with inductor has a very small $X_L$

so

We get,localid="1649933493454" $$\begin{gathered} Z=R_1 \\ I=\frac{10}{100} \\ I\hspace{0.17em}=0.10A \end{gathered}$$

Hence the current is$0.10A$.

We are given that the values of $R_1=100\Omega$,$R_2=50\Omega$,localid="1650185571185" ${\epsilon }_o=10V$

and we have to find the current supplied by emf when the frequency is very large .

When the frequency is very large then the branch with capacitor has a very small

so $Z=R_2$

$$\begin{gathered} I_{rms}=\frac{10}{50} \\ {I}_{rms}=0.20A \end{gathered}$$On solving we get,

Hence the current is $0.20A$.