Chapter 32: Q. 63 (page 926)

A generator consists of a $12 c m$ by $16 c m$ rectangular loop with $500$ turns of wire spinning at $60 H z$ z in a $25 m T$ uniform magnetic field. The generator output is connected to a series RC circuit consisting of a $120 o h m$ resistor and a $35 m F$ capacitor. What is the average power delivered to the circuit?

Short Answer

Expert verified

The average power delivered to the circuit is :-

$P_{a v g} = 24$ W

Step by step solution

Given information

We have been given that a generator consists of a $12 c m$ by $16 c m$ rectangular loop with $500$ turns of wire spinning at $60 H z$ in a $25 m T$ uniform magnetic field. The generator output is connected to a $120 o h m$ series RC circuit consisting of a resistor and a $35 m F$ capacitor. We have to find the average power delivered to the circuit.

Simplification

The voltage and current is:

$I_{rms} = \frac{ε_{rms}}{\sqrt{R^{2} + X_{C}^{2}}}$

$ε_{o} = N B A ω$

$= 90.48 V$

To find the expression :

$P_{avg} = I_{rms}^{2} R$

$= \frac{ε_{o}^{2} R}{2 (R^{2} + (1 / 2 π f C)^{2})}$

$= \frac{(90.48 V)^{2} (120 Ω)}{2 [(120 Ω)^{2} + {(1 / 2 π (60 Hz) (35 \times 10^{- 6} F))}^{2}]}$

$= 24 W$

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A generator consists of a 12cm by 16cmrectangular loop with 500 turns of wire spinning at 60Hzz in a 25mTuniform magnetic field. The generator output is connected to a series RC circuit consisting of a120ohm resistor and a 35mF capacitor. What is the average power delivered to the circuit?

Short Answer

Step by step solution

Given information

Simplification

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Wave Optics

Atoms and Radioactivity

Dynamics

Electricity and Magnetism

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Study anywhere. Anytime. Across all devices.