Commercial electricity is generated and transmitted as three-phase electricity. Instead of a single emf, three separate wires carry currents for the emfs E1=E0cosvt,E2=E0cos1vt+120°,andE3=E0cos1vt-120°over three parallel wires, each of which supplies one-third of the power. This is why the long-distance transmission lines you see in the countryside have three wires. Suppose the transmission lines into a city supply a total of 450MWof electric power, a realistic value.

a. What would be the current in each wire if the transmission voltage were E0=120Vrms?

b. In fact, transformers are used to step the transmission-line voltage up to 500kVrms. What is the current in each wire?

c. Big transformers are expensive. Why does the electric company use step-up transformers?

Short Answer

Expert verified

(a.) The value of current in each wire is Irms=1.25×106A.

(b.) When transformer are used then the current in each wire is Irms=300A.

(c.) Copper may be a good conductor , but it still have some resistance.

Step by step solution

01

Part (a) Step 1: Given information

We are given that a commercial electricity is generated and transmitted as three-phase electricity. Instead of a single emf, three separate wires carry currents for the emfsE1=E0cosvt,E2=E0cos1vt+120°,andE3=E0cos1vt-120° over three parallel wires, each of which supplies one-third of the power. This is why the long-distance transmission lines you see in the countryside have three wires. Suppose the transmission lines into a city supply a total of 450MWof electric power, a realistic value.

What would be the current in each wire if the transmission voltage were E0=120Vrms.

02

Part (a) Step 1: Explanation

We need to find what is the current in each wire when step the transmission line up to500kVrms.

P=Irms×Erms+(Irms×Erms)2+(Irms×Erms)3P=3Irms×Erms450×10-6=3×Irms×120Irms=1.25×106A

03

Part (b) Step 1: Given information

We are given that a transformers are used to step the transmission-line voltage up to 500kVrmsWe need to find What is the current in each wire.

04

Part (b) Step 2: Explanation

We use same equation

P=Irms×Erms+(Irms×Erms)2+(Irms×Erms)3

P=3Irms×Erms450×10-6=3×Irms×500×103Irms==300A

05

Part (c) Step 1: Given information

We need to find Big transformers are expensive. Why does the electric company use step-up transformers?

06

Part (c) Step 2: Explanation

Because Copper may be a good conductor , but it still have some resistance .

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