Chapter 32: Q. 7 (page 924)

The peak current to and from a capacitor is $10 m A$ . What is the peak current if
a. The emf frequency is doubled?
b. The emf peak voltage is doubled (at the original frequency)

Short Answer

Expert verified

Result is:

$a.) I_{o}^{'} = 20 mA$

$b.) I_{o}^{'} = 20 mA$

Step by step solution

Part (a) Step 1: Given information

We have been given that $I_{o} = 10 mA$

we will use the formula to sovle is:

$I_{o} = (2 π f) V_{o} C and I_{o} α f$

Part(a) Step 2: Simplify

if $f$ is the frequency doubled:

$I_{o}^{'} = 2 \cdot I_{o}$

As, $I_{o}^{} = 10 m A$

$I_{o}^{'} = 2 \cdot 10 m A$

$I_{o}^{'} = 20 m A$

Part (b) Step 1: Given information

We have been given that $I_{0} = 10 mA$

According to the formula:

$I_{o} = (2 π f) V_{o} C and I_{o} α f$

Part (b) Step 2: Simplify

$I_{o} α V_{o} \Rightarrow V_{o} (doubled) \Rightarrow I_{o}^{'} = 2 I_{o}$

$I_{o}^{'} = 2 \cdot 10 mA$

$I_{o}^{'} = 20 m A$

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The peak current to and from a capacitor is $10 m A$ . What is the peak current if
a. The emf frequency is doubled?
b. The emf peak voltage is doubled (at the original frequency)

Short Answer

Step by step solution

Part (a) Step 1: Given information

Part(a) Step 2: Simplify

Part (b) Step 1: Given information

Part (b) Step 2: Simplify

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The peak current to and from a capacitor is 10mA. What is the peak current ifa. The emf frequency is doubled?b. The emf peak voltage is doubled (at the original frequency)

Short Answer

Step by step solution

Part (a) Step 1: Given information

Part(a) Step 2: Simplify

Part (b) Step 1: Given information

Part (b) Step 2: Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Classical Mechanics

Circular Motion and Gravitation

Atoms and Radioactivity

Dynamics

Energy Physics

Wave Optics

Study anywhere. Anytime. Across all devices.

The peak current to and from a capacitor is $10 m A$ . What is the peak current if
a. The emf frequency is doubled?
b. The emf peak voltage is doubled (at the original frequency)