An inductor is connected to a 15kHzoscillator. The peak current is 65mA when the rms voltage is 6.0V. What is the value of the inductance L?

Short Answer

Expert verified

The value of Inductance isL=1.38mH

Step by step solution

01

Given information 

We have been given that

Frequency of oscillator is f=15KHz

Value of peak current I∘=65mA

RMS VoltageVrms=6.0V

We need to find out the inductance of an inductor connected to an oscillator

02

Detailed solution 

As we know that Inductive Reactance; XL=2Ï€fLwhere f is frequency of oscillator and L is inductance

⇒L=XL2πf......(1)

Also,

XL=VmaxImax⇒XL=2VrmsImax......(2)where Vrms=6V;Imax=65mA

On Putting (2) in (1) we get,

localid="1649880677194" width="356">L=2VrmsImax(2πf)=2×665×10-3×2×3.14×15×1000L=1.38mH

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