Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 41: Q. 15 (page 1207)

What is the electron configuration of the second excited state of lithium?

Short Answer

Expert verified

The electronic configuration of second excited state for lithium atom is1s23s1

Step by step solution

01

Step 1. Given information

The number of possible electrons in sorbital (or shell) is 2 ,

the number of possible electrons in porbital (or shell) is 6 ,

the number of possible electrons in orbital (or shell) is 10,

and the number of possible electrons in gorbital (or shell) is 14 .

02

Step 2. Explanation

We must determine the electron configuration of lithium's second exited state.

In the ground state, the lithium atom (Z= 3) contains two electrons in the 1s shell and one electron in the 2s shell.

For the first excited state of lithium, the electron configuration is:

1s22p

As a result, the electron configuration for lithium's second excited state is:

1s23s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Prove that the normalization constant of the 1sradial wave function of the hydrogen atom is localid="1650358688008" πaB3-1/2, as given in Equations 41.7.

Three electrons are in a one-dimensional rigid box (i.e., an infinite potential well) of length 0.50nm. Two are in the n = 1 state and one is in the n = 6 state. The selection rule for the rigid box allows only those transitions for which n is odd.

a. Draw an energy-level diagram. On it, show the filled levels and show all transitions that could emit a photon.

b. What are all the possible wavelengths that could be emitted by this system?

In a multielectron atom, the lowest-lstate for eachn2s,3s,4s,etc.is significantly lower in energy than the hydrogen state having the same n. But the highest-l state for each n(2p,3d,4fetc) is very nearly equal in energy to the hydrogen state with the same n. Explain.

Suppose you have a machine that gives you pieces of candy when you push a button. Eighty percent of the time, pushing the button gets you two pieces of candy. Twenty percent of the time, pushing the button yields 10pieces. The average number of pieces per push is Navg=2×0.80+10×0.20=3.6. That is, 10pushes should get you, on average, 36pieces. Mathematically, the average value when the probabilities differ is Navg=∑(Ni×Probabilityofi). We can do the same thing in quantum mechanics, with the difference that the sum becomes an integral. If you measured the distance of the electron from the proton in many hydrogen atoms,

you would get many values, as indicated by the radial probability density. But the average value of rwould be

ravg0=∫0∞rPr(r)dt

Calculate the average value of rin terms of aBfor the electron in the 1sand the 2pstates of hydrogen.

In FIGURE Q41.12,a photon with energy 2.0eVis incident on an atom in the pstate. Does the atom undergo an absorption transition, a stimulated emission transition, or neither? Explain.

See all solutions

Recommended explanations on Physics Textbooks

Electric Charge Field and Potential

Read Explanation

Turning Points in Physics

Read Explanation

Nuclear Physics

Read Explanation

Modern Physics

Read Explanation

Geometrical and Physical Optics

Read Explanation

Particle Model of Matter

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free