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Chapter 41: Q. 23 (page 1207)

A 1.0mW helium-neon laser emits a visible laser beam with a wavelength of 633nm. How many photons are emitted per second?

Short Answer

Expert verified

No of photons emitted per second are

N=3.34×1015

Step by step solution

01

Given information

We have given that,

P=1mW=10-3Wλ=633nm=633×10-9m

We have to find the no, of photons emitted per second.

02

Simplification

Since P=0.0010W, the laser light emits Elight=0.0010Jof light energy per second.

This energy consists of Nphotons. The energy of each photon is

E=hf=hcλ=3.14×10-19J

As Elight=NEphoton,the no. of photons is

N=ElightEphoton=0.0010J3.13×10-19J=3.2×1015

So, the photons are emitted at the rate of3.2×1015s-1.

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Most popular questions from this chapter

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a. What is the magnitude (as a multiple ofrole="math" localid="1650369219275" ♄ ) of the spin angular momentum Sfor a particle with a spin of one?

b. What are the possible values of the spin quantum number?

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