Chapter 41: Q. 8 (page 1207)

Predict the ground-state electron configurations of $M g, S r$ and $B a$ ?

Short Answer

Expert verified

The ground-state electron configurations of $M g$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$ , $S r$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2}$ and $B a$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p^{6} 6 s^{2}$ .

Step by step solution

Given Information

We need to find the ground-state electron configurations of $M g, S r$ and $B a$ .

Simplify

The electron configurations for $M g, S r$ and $B a$ .

First, finding electron configuration for $M g (Z = 12)$ :

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$

Total electrons is $(2 + 2 + 6 + 2 = 12)$ .

Now, finding electron configuration for role="math" localid="1650270308995" $S r (Z = 38)$ :

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2}$

Total electrons is $(2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 = 38)$

At last , finding electron configuration for $B a (Z = 56)$ .

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p^{6} 6 s^{2}$

Total electrons is $(2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 6 + 2 = 56)$

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Predict the ground-state electron configurations of $M g, S r$ and $B a$ ?

Short Answer

Step by step solution

Given Information

Simplify

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Predict the ground-state electron configurations of $M g, S r$ and $B a$ ?