Chapter 41: Q. 9 (page 1207)

Predict the ground-state electron configurations of $A l, G n$ and $I n$ ?

Short Answer

Expert verified

The ground-state electron configurations of $A l$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p$ , $G n$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p 4 s^{2} 3 d^{10} 4 p$ and $I n$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p$ .

Step by step solution

Given Information

We need to find the ground-state electron configurations of $A l, G n$ and $I n$ .

Simplify

The electron configuration for $A l, G n$ and $I n$ .

First, finding the electron configuration for $A l (Z = 13)$ :

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p$

Total numbers of electron is $(2 + 2 + 6 + 2 + 1 = 13)$ .

Now, finding the electron configuration for $G n (Z = 31)$ :

role="math" localid="1650271286398" $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p 4 s^{2} 3 d^{10} 4 p$

Total number of electron is $(2 + 2 + 6 + 2 + 6 + 2 + 10 + 1 = 31)$

At last, finding the electron configuration for role="math" localid="1650271252311" $\ln (Z = 49)$ :
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p$

Total number of electron is $(2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 1 = 49)$

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Predict the ground-state electron configurations of $A l, G n$ and $I n$ ?

Short Answer

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Predict the ground-state electron configurations of $A l, G n$ and $I n$ ?