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Chapter 27: Q. 12 (page 762)

The current in an electric hair dryer is $10.0 A$ . How many electrons flow through the hair dryer in $5.0$ min?

Short Answer

Expert verified

The number of electrons flows through the hairdryer in $5.0 m i n$ is $1.875 \times 10^{22} .$

Step by step solution

01

Given Information

Current $= 10.0 A$

Time $= 5.0 m i n$

02

Explanation

The number of charges is connected to the total charge,

$Q = N e \Rightarrow N = \frac{Q}{e}$

By the definition of intensity, express the charge passed at a given time as a function of the intensity as

$I : = \frac{Q}{t} \Rightarrow Q = I t$

In combining, we have

$N = \frac{I t}{e}$

Substitute the values,

role="math" $N = (\frac{10 A \times 5 s \times 60 s}{1.6 \times 10^{- 19} C})$

role="math" localid="1648897689414" $= 1.875 \cdot 10^{22}$

03

Final Answer

Hence, the number of electrons flows through the hairdryer in $5 m i n$ is $1.875 \cdot 10^{22} .$

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Most popular questions from this chapter

75. A $300 μ F$ capacitor is charged to $9.0 V$ , then connected in parallel with a $5000 Ω$ resistor. The capacitor will discharge because the resistor provides a conducting pathway between the capacitor plates, but much more slowly than if the plates were connected by a wire. Let $t = 0 s$ be the instant the fully charged capacitor is first connected to the resistor. At what time has the capacitor voltage decreased by half, to $4.5 V$ ?
Hint: The current through the resistor is related to the rate at which charge is leaving the capacitor. Consequently, you'll need a minus sign that you might not have expected.

Is FIGURE Q27.4 a possible surface charge distribution for a current-carrying wire? If so, in which direction is the current? If not, why not?

Electrons flow through a $1.6 m m$ diameter aluminum wire atrole="math" localid="1648804486550" $2.0 \times 10^{- 4} m / s$ . How many electrons move through a cross-section of the wire each day?

A $0.60$ -mm-diameter wire made from an alloy (a combination of different metals) has a conductivity that decreases linearly with distance from the center of the wire: $σ (r) = σ_{0} - c r$ , with $σ_{0} = 5.0 \times 10^{7} Ω^{- 1} m^{- 1}$ and $c = 1.2 \times 10^{11} Ω^{- 1} m^{- 2}$ . What is the resistance of a $4.0 m$ length of this wire?

The femoral artery is the large artery that carries blood to the leg. What is the resistance of a $20 c m$ long column of blood in a 1.0-cm-diameter femoral artery? The conductivity of blood isrole="math" localid="1649056084708" $0.63 Ω^{- 1} m^{- 1} .$

See all solutions

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