21. A 0.0075V/m electric field creates a 3.9mA current in a 1.0-mm-diameter wire. What material is the wire made of?

Short Answer

Expert verified

The material is the wire made of Nichrome.

Step by step solution

01

Given information

The electric field in the wire is 0.0075V/m.The current through the wire is 3.9mA. The diameter of the wire is 1.0-mm-diameter wire.

So, the radius isr=0.5mm=5×10-4m.

02

Explanation

Determine the material from its conductivity σ by,
J=σE(1)
whereJ=Iπr2is the current density . That means the current per square meter passing through a cross section of the wire -- andE is the electric field strength in the material.
Plugging the formula for the current density into equation (1) and solving for σ,
σ=IEπr2(2)

03

Explanation

The Calculation: Now we can simply plug these values into equation (2):σ=IEπr2
=3.9×103A(0.0075V/m)π5×104m2

=6.6×105Ω1×m1

The only material with a conductivity near6.6×105Ω-1×m-1 is Nichrome.
04

Final answer

The material the wire is made from Nichrome.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

25. A 1.5Vbattery provides 0.50A of current.
a. At what rate (C/s) is charge lifted by the charge escalator?
b. How much work does the charge escalator do to lift 1.0C of charge?
c. What is the power output of the charge escalator?

26. Wires 1 and 2 are made of the same metal. Wire2 has twice the length and twice the diameter of wire 1. What are the ratios (a) ρ2/ρ1 of the resistivities and (b) R2/R1 of the resistances of the two wires?

73. A 5.0-mm-diameter proton beam carries a total current of 1.5mA. The current density in the proton beam, which increases with distance from the center, is given by J=Jedge(r/R), where R is the radius of the beam and Jedge is the current density at the edge.
a. How many protons per second are delivered by this proton beam?
b. Determine the value of Jedge.

56. A hollow metal cylinder has inner radius a, outer radius b, length L, and conductivityσ. The current Iis radially outward from the inner surface to the outer surface.
a. Find an expression for the electric field strength inside the metal as a function of the radius r from the cylinder's axis.
b. Evaluate the electric field strength at the inner and outer surfaces of an iron cylinder if a=1.0cm,b=2.5cm,L=10cm,and I=25A.

The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivities of muscle and fat are 13 Ω m and 25 Ω m, respectively. One person’s upper leg is 82% muscle, 18% fat. What current is measured if a 1.5 V potential difference is applied between the person’s hip and knee?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free