1.0×1016electrons flow through a cross section of a silver wire in 320μs with a drift speed of 8.0×10-4m/s. What is the diameter of the wire?

Short Answer

Expert verified

The diameter of the wire is0.93mm.

Step by step solution

01

Given Information

Number of electrons=1.0×1016

Time=320μs

Drift speed=8.0×10-4m/s

02

Explanation

The electron density is

ie:=Nt

The current density is known to be

ie=neAvd.

The area of a circle is,

A=πD24D=4Aπ.

Write the area as

A=ienevd

Write the electron current and substitute,

A=Nnetvd

Now, substituting this expression for the area at the one for the diameter,

D=4Nπnetvd.

After substituting the values,

localid="1649322696741" D=4×1×1016eπ×5.8×1028e×3.2×10-4μs×8×10-4m/s

localid="1649322704585" =9.26×10-4m.

03

Final Answer

Hence, the diameter of the wire is9.26×10-4m.

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