A20-cm-long hollow nichrome tube of inner diameter 2.8mm, outer diameter3.0mmis connected, at its ends, to a 3.0Vbattery. What is the current in the tube?

Short Answer

Expert verified

The current in the tube isI=36A.

Step by step solution

01

Given information

Nichrome tube length =20cm

Nichrome tube inner diameter=2.8mm

Nichrome tube outer diameter=3.0mm

Voltage=3.0V

02

Explanation

Use the I=VR(1)formula,

The area of the tube is provided by the area of the outer circle D=3.0mmminus the area of the inner circle d=2.8mm:

A=0.0032×π-0.00282×π

role="math" localid="1649165023302" A=3.64×10-6m2

Find the resistance of this tube,

R=(ρ×LA

Where Lis the length of the wire and Ais the outer area minus the inner area and rho is the resistivity of nichrome.

role="math" localid="1649165124828" R=1.5Ωm×10-6×0.02m3.64×10-6m2

R=0.0823Ω

Substitute the value in equation (1)

I=3V0.0823Ω

I=36.44A

03

Final Answer

Hence, the current in the tube is36A.

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