A 60kgskater is gliding across frictionless ice at 4.0m/s. Air resistance is not negligible. You can model the skater as a 170cm-tall,36cm-diameter cylinder. What is the skater's speed2.0s later?

Short Answer

Expert verified

Speed of the skater after2Sec is3.4m/s.

Step by step solution

01

:Given.

Mass of the skater, m=60kg.

Speed of the skater, v=4m/s.

Diameter of the skater, d=36cm.

Height of the skater,h=170cm.

02

Formula used.

The air friction is given by the formula:

F=12ρ×A×v2

Here,

ρis the density of air.

Ais the surface area of the cylinder.

vis the velocity of the skater.

03

Calculation.

The surface area of the skater is calculated as:A=πdH

Plugging the values in the above equation,

A=π×0.36×1.7=1.92m2.

Now drag force due to air is calculated as:

F=12×1.2×1.92×42=18.43N.

The deceleration on the skater due to air friction is calculated as:

F=ma18.43=60×aa=0.30m/s2.

The speed of the skater after 2sec is calculated as:

role="math" localid="1647774441411" v=uat=40.3×2=3.4m/s.

04

Conclusion.

Speed of the skater after 2sec is3.4m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free