Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 6: Q.27 (page 155)

Bob is pulling a 30kgfiling cabinet with a force of 200N, but the filing cabinet refuses to move. The coefficient of static friction between the filing cabinet and the floor is 0.80. What is the magnitude of the friction force on the filing cabinet?

Short Answer

Expert verified

The magnitude of the friction force on the filling cabinet isfs=235.2N

Step by step solution

01

Content Introduction

The friction force is proportional to the normal force N exerted by the wall against the block. According to Newton's third law, normal force is equal to and opposite in direction to the force exerted on the wall by the block, which is dependent on F and θ. The friction force will be directed in the opposite direction as the motion.

02

Content Explanation

We are given:

m=30kgis mass,FN=200Nis force,μs=0.80is the coefficient of friction

The magnitude of the friction force on the filling cabinet is

fs=μsFN∑fy=0

Since all forces are in equilibrium, we got

FN-mg=0FN=30×9.81FN=294N

Solve for the magnitude of friction force on the filling cabinet,

fs=0.8×294fs=235.2N

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An accident victim with a broken leg is being placed traction. The patient wears a special boot with a pulley attached to the sole. The foot and boot together have a mass of 4.0 kg and the doctor has decided to hang a 6.0 kg mass from the rope. The boot is held suspended by the ropes, as shown in FIGURE P6.41, and does not touch the bed a. Determine the amount of tension in the rope by using Newton’s laws to analyze the hanging mass. b. The net traction force needs to pull straight out on the leg. What is the proper angle u for the upper rope? c. What is the net traction force pulling on the leg? Hint: If the pulleys are frictionless, which we will assume, the tension in the rope is constant from one end to the other.
  1. Write a realistic problem for which these are the correct equations.
  2. Draw the free-body diagram and the pictorial representation for your problem.
  3. Finish the solution of the problem.

T−0.20n−(20kg)(9.80m/s2)sin⁡20∘

=(20kg)(2.0m/s2)n−(20kg)(9.80m/s2)cos⁡20∘=0

A person with compromised pinch strength in his fingers can exert a force of only6.0Nto either side of a pinched object, such as the book shown in FIGURE P6.58. What is the heaviest book he can hold vertically before it slips out of his fingers? The coefficient of static friction between his fingers and the book cover is 0.80.

FIGURE P6.58

Compressed air is used to fire a 50 g ball vertically upward from a 1.0 m-tall tube. The air exerts an upward force of 2N on the ball as long as it is in the tube. How high does the ball go above the top of the tube?

A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1000N, the players have equal pulls, and the angle between the two ropes is 20°. How hard must each player pull to drag the coach at a steady2.0m/s?
See all solutions

Recommended explanations on Physics Textbooks

Quantum Physics

Read Explanation

Translational Dynamics

Read Explanation

Astrophysics

Read Explanation

Force

Read Explanation

Radiation

Read Explanation

Physics of Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free