The 1000 kg steel beam is supported by two ropes. What is the tension in each?

Short Answer

Expert verified

Tension in rope 1 is6035.5N

Tension in rope 2 is4128.5N

Step by step solution

01

Given information

Weight of beam-=1000KG

Angle between rope 1and perpendicular is20°

Angle between rope 2and perpendicular is30°

02

Assumptions

Let rope 1 be R1and rope 2be R2.

Tension of rope 1=TR1

Tension of rope 2=TR2

Point 0(mg)is where two ropes are connected.

03

Calculation of tension in each rope

Atpoint0

fx=0

localid="1649397086445" TR1sin20°=localid="1649397058574" TR2sin30°

localid="1649614498151" TR2=localid="1649614527752" role="math" 2×TR1localid="1648026003669" sin20°eq.1

fx=0

localid="1649614427856" TR1cos(30)+localid="1649396955821" TR2cos30°=mg

localid="1649396975732" TR1cos20°+2TR1sin20°=1000×9.8

Tension in rope 1

TR1is 6035.5N

Tension in rope 2 TR2-

localid="1649397189749" TR2=localid="1649396688322" 2×6035.5×sin20°

Tension in rope 2

TR2is 4128.5N

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

  1. Write a realistic problem for which these are the correct equations.
  2. Draw the free-body diagram and the pictorial representation for your problem.
  3. Finish the solution of the problem.

T0.20n(20kg)(9.80m/s2)sin20

=(20kg)(2.0m/s2)n(20kg)(9.80m/s2)cos20=0

A large box of mass Mis pulled across a horizontal, frictionless surface by a horizontal rope with tension T. A small box of mass m sits on top of the large box. The coefficients of static and kinetic friction between the two boxes are μsand μk, respectively. Find an expression for the maximum tension Tmaxfor which the small box rides on top of the large box without slipping.

A ball is shot from a compressed-air gun at twice its terminal speed.

a. What is the ball's initial acceleration, as a multiple of g, if it is shot straight up?

b. What is the ball's initial acceleration, as a multiple of g, if it is shot straight down?

  1. Write a realistic problem for which these are the correct equations.
  2. Draw the free-body diagram and the pictorial representation for your problem.
  3. Finish the solution of the problem.
(100N)cos30fk=(20kg)ax

n+(100N)sin30(20kg)(9.80m/s2)=0fk=0.20n.

An accident victim with a broken leg is being placed in traction. The patient wears a special boot with a pulley attached to the sole. The foot and boot together have a mass of 4.0kg, and the doctor has decided to hang a 6.0kgmass from the rope. The boot is held suspended by the ropes, as shown in FIGUREP6.41, and does not touch the bed.

a. Determine the amount of tension in the rope by using Newton’s laws to analyze the hanging mass.

b. The net traction force needs to pull straight out on the leg. What is the proper angle u for the upper rope?

c. What is the net traction force pulling on the leg?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free