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Chapter 8: Q.27 (page 199)

A toy train rolls around a horizontal 1.0-m-diameter track. The coefficient of rolling friction is 0.10. How long does it take the train to stop if it’s released with an angular speed of 30 rpm?

Short Answer

Expert verified

The train will take 1.61sto stop if it’s released with an angular speed of 30rpm.

Step by step solution

01

Given Information

A toy train rolls around a horizontal 1.0-m-diameter track. The coefficient of rolling friction is 0.10.

02

Explanation

According to the information

Initial speed μ=30rpm

Diameter d=1.0m

Radius R=12=0.5

Convert rpm to rad/s as follow:

(30rpm)=30(2π)60

=3.15rad/s

The time take is expressed as follow:

T=3.151.96rad/s2

T=1.61s

03

Final Answer

The train will take 1.61sto stop if it’s released with an angular speed of30rpm.

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Most popular questions from this chapter

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