A new car is tested on a 200-m-diameter track. If the car speeds up at a steady 1.5m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?

Short Answer

Expert verified

The magnitude of its centripetal acceleration equal to the tangential acceleration after8.2s.

Step by step solution

01

Given Information

Diameter of the track : d=200m.

Acceleration of the car at=1.5m/s2.

02

Explanation

According to the information:

d-The diameter of the truck =200m

at-Tangential acceleration=1.5m/s2

The centripetal accelerationac is given as follow:

ac=v2r

Where,

v-The velocity of the car

r-The radius of the track

t-The time

03

Applying the equation to find time

Centripetal acceleration ac=Tangential acceleration at

at=v2r

v=at×r (1)

The initial velocity of the car is zero.

Therefore, the tangential acceleration is given by kinematic equation as follow:

v=at×t (2)

From equation 1 and 2, we get

at×r=at×t

t=rat

t=d2at

t=2002×1.5

t=66.67

t=8.2s

04

Final Answer

The magnitude of its centripetal acceleration equal to the tangential acceleration after8.2s.

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