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Chapter 22: Q. 26 - Excercises And Problems (page 625)

What are the strength and direction of the electric field 1.0 mm from (a) a proton and (b) an electron?

Short Answer

Expert verified

a. the strength of the electric field for proton E=1.44×10-3N/C. The electric field due to the electron is directed radially away from the proton.

b. the strength of the electric field for electron E=-1.44×10-3N/C. The electric field due to the electron is directed radially towards the electron.

Step by step solution

01

Given information

proton is at distance 1.00 mm

electron is at distance 1.00 mm

02

Explanation (part a)

Strength of electric field can be calculated as

E=KQr2E=8.99×109N.m2/C21.6×10-19C1.0×10-3m2E=1.44×10-3N/C

03

Explanation (part b)

As the magnitude of the charge on the electron and proton is same but with opposite sign. So the magnitude of the electric field due to the electron is the same as the magnitude of the electric field due to the proton, at equal distances but in opposite direction.

The electric field due to the electron is directed radially towards the electron.

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