Chapter 22: Q. 39 (page 625)

A smart phone charger delivers charge to the phone, in the form of electrons, at a rate of $- 0.75 C / s$ . How many electrons are delivered to the phone during $30 \min$ of charging?

Short Answer

Expert verified

Delivered electrons are $8.4 \times 10^{21} electrons$ .

Step by step solution

Calculation for charge

Charge is,

$Q = N e$

Where $e = - 1.6 \times 10^{- 19} C$ .

So,

$N = \frac{Q}{e}$

The rate of accumulation of the electrons is ,

$\frac{Q}{t}$

$= - 0.75 C / s$

For time $t = 30 \min$ ,

Where,

$t = 30 \min = 30 (60 s)$

$= 1800 s$

So,

$Q = (- 0.75 C / s) t$

$= (- 0.75 C / s) (1800 s)$

$= - 1350 C$

Calculation of electrons

Electron is,

$N = \frac{Q}{e}$

$= \frac{- 1350 C}{- 1.6 \times 10^{- 19} C}$

$= 8.4 \times 10^{21} electrons$

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A smart phone charger delivers charge to the phone, in the form of electrons, at a rate of $- 0.75 C / s$ . How many electrons are delivered to the phone during $30 \min$ of charging?

Short Answer

Step by step solution

Calculation for charge

Calculation of electrons

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A smart phone charger delivers charge to the phone, in the form of electrons, at a rate of-0.75C/s . How many electrons are delivered to the phone during 30min of charging?

Short Answer

Step by step solution

Calculation for charge

Calculation of electrons

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Mechanics and Materials

Torque and Rotational Motion

Electricity and Magnetism

Radiation

Measurements

Space Physics

Study anywhere. Anytime. Across all devices.

A smart phone charger delivers charge to the phone, in the form of electrons, at a rate of $- 0.75 C / s$ . How many electrons are delivered to the phone during $30 \min$ of charging?