What is the forceFon the1.0nCcharge at the bottom in FIGURE P22.45?Give your answer in component form.

Short Answer

Expert verified

Force on1.0nCisFon1=1.1×10-5j^N.

Step by step solution

01

Figure for force on the1.0 nccharge

Figure is,

02

Calculation of force on q2andq3

Putting a charge of1.0nCat the origin and labelling itq1.

For chargeq2:

F2on1=kq1q2r2i^

=9×1091×10-92×10-95×10-22-cos45°i^-sin45°j^

=0.72×105N-cos45°i^-sin45°j^

For chargelocalid="1649089752680" q3:

F3on1=9×1091×10-96×10-95×10-22j^N

=2.16×10-5j^N

03

Force for chargeq4andq1

For charge q4:

F4on1=0.72×10-5Ncos45°i^-sin45°j^

For charge q1:

Fon1=F2on1+F3on1+F4on1

Fon1=1.1×10-5j^N

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