Chapter 22: Q. 49 (page 626)

Charge $q_{2}$ in FIGURE $P 22.49$ is in equilibrium. What is $q_{1}$ $?$

Short Answer

Expert verified

Charge is $- 20 nC$ .

Step by step solution

Calculation for force on charge

Two charged particles, one with a charge of $q_{1}$ .

And the other with a charge of $q_{2}$ , separated by a distance of $r$ .

The two particles exert forces on each other, with the force decreasing as the distance between them grows and increasing as the size of the charges increases.

$F_{C} = F_{1 on 2} = F_{2 on 1} = \frac{K |q_{1}| |q_{2}|}{r^{2}}$

Force for charge $q_{3}$ and $q_{2}$ :

${\vec{F}}_{32} = \frac{{Kq}_{3} q_{2}}{r_{32}^{2}}$

$= \frac{(9.0 \times 10^{9} N \cdot m^{2} / C^{2}) (5 \times 10^{- 9} C) q_{2}}{(0.1 m)^{2}}$

$= 4500 q_{2}$

Calculation of charge

Force for charge $q_{1}$ and $q_{2}$

${\vec{F}}_{12} = \frac{{Kq}_{1} q_{2}}{r_{12}^{2}}$

$= \frac{(9.0 \times 10^{9} N \cdot m^{2} / C^{2}) q_{1} q_{2}}{(0.2 m)^{2}}$

$= 225 \times 10^{9} q_{1} q_{2}$

{\vec{F}}_{12} = - {\vec{F}}_{32}

so,

${\vec{F}}_{12} = - {\vec{F}}_{32}$

$225 \times 10^{9} q_{1} q_{2} = - 4500 q_{2}$

$q_{1} = - \frac{4500}{225 \times 10^{9}}$

$q_{1} = - 20 \times 10^{- 9} C$

$q_{1} = - 20 nC$

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Charge $q_{2}$ in FIGURE $P 22.49$ is in equilibrium. What is $q_{1}$ $?$

Short Answer

Step by step solution

Calculation for force on charge

Calculation of charge

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Chargeq2in FIGUREP22.49is in equilibrium. What isq1?

Short Answer

Step by step solution

Calculation for force on charge

Calculation of charge

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Dynamics

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Particle Model of Matter

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Energy Physics

Study anywhere. Anytime. Across all devices.

Charge $q_{2}$ in FIGURE $P 22.49$ is in equilibrium. What is $q_{1}$ $?$