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Chapter 31: Q. 12 (page 901)

What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 10V/m ?

Short Answer

Expert verified

The magnetic field amplitude of an electromagnetic wave is3.33×10-8T.

Step by step solution

01

Step 1: 

As it stand's,

E=10V/m

c=3×108m/s

Electric field amplitude,

E=c·B

B-Magnitude field of amplitude.

localid="1648801389365" c-In a vacuum, the speed of light

02

Calculation of magnetic field amplitude

Electric field amplitude is,

E=c·B

from the formula,

both to be divided byc,

Ec=c·Bc

B=Ec

B=10V/m3×108m/s

B=3.33×10-8T

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Most popular questions from this chapter

A wire with conductivity s carries current I. The current is increasing at the rate dI/dt.

a. Show that there is a displacement current in the wire equal to (∈o/σ)(dI/dt)

b. Evaluate the displacement current for a copper wire in which the current is increasing at 1.0×106A/s.

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a. What are E→and B→at a point on the loop as measured by a scientist in the laboratory? Include both strength and direction.

b. What are the fields E→and B→at a point on the loop as measured by a scientist in the frame of the loop?

c. Show that an experimenter in the loop’s frame sees a currentI=λνpassing through the center of the loop.

d. What electric and magnetic fields would an experimenter in the loop’s frame calculate at distance r from the current of part c?

e. Show that your fields of parts b and d are the same.

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