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Chapter 31: Q. 27 (page 902)

A200mWvertically polarized laser beam passes through a polarizing filter whose axis is 35° from horizontal. What is the power of the laser beam as it emerges from the filter?

Short Answer

Expert verified

The power of the laser beam is65.8mw.

Step by step solution

01

Formula for power of laser beam

When unpolarized light strikes a polarizer, the power of the polarised light that emerges is half that of the unpolarized light.

Incident light that isn't polarised.

So,

P=P0cos2θ

Where,

role="math" localid="1648929202807" P0-Vertically polarized laser beam

P-Power of laser beam

02

Figure for laser beam with axis of 35°

Figure is,

03

Calculation for power of laser beam

The beam angle is,

θ=90°-35°

=55°

The beam's power is determined as follows:

P=P0cos2θ

=200mW×cos255°

P≈65.8mW

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Most popular questions from this chapter

When the Voyager 2spacecraft passed Neptune in 1989, it was 4.5×109kmfrom the earth. Its radio transmitter, with which it sent back data and images, broadcast with a mere 21Wof power. Assuming that the transmitter broadcast equally in all directions,

a. What signal intensity was received on the earth?

b. What electric field amplitude was detected?

The received signal was somewhat stronger than your result because the spacecraft used a directional antenna, but not by much.

Only 25%of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter?

The magnetic field inside a 4.0 cm diameter superconducting solenoid varies sinusoidally between 8.0Tand12.0Tat a frequency of10Hz.12.0T

a. What is the maximum electric field strength at a point 1.5cm from the solenoid axis?

b. What is the value of localid="1650012451022" Bat the instant localid="1650084655519" Ereaches its maximum value?

A proton is fired with a speed of 1.0×106m/sthrough the parallel-plate capacitor shown in FIGURE P31.31. The capacitor's electric field is role="math" localid="1648984502437" E→=1.0×105V/m,down).

a. What magnetic field B→, both strength and direction, must be applied to allow the proton to pass through the capacitor with no change in speed or direction?

b. Find the electric and magnetic fields in the proton's reference frame.

c. How does an experimenter in the proton's frame explain that the proton experiences no force as the charged plates fly by?

In FIGURE P31.33, a circular loop of radius rtravels with speed valong a charged wire having linear charge density I. The wire is at rest in the laboratory frame, and it passes through the center of the loop.

a. What are E→and B→at a point on the loop as measured by a scientist in the laboratory? Include both strength and direction.

b. What are the fields E→and B→at a point on the loop as measured by a scientist in the frame of the loop?

c. Show that an experimenter in the loop’s frame sees a currentI=λνpassing through the center of the loop.

d. What electric and magnetic fields would an experimenter in the loop’s frame calculate at distance r from the current of part c?

e. Show that your fields of parts b and d are the same.
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