What are the electric field strength and direction at the position of the electron in FIGUREP31.28?

Short Answer

Expert verified

Electric field strength in figureP31.8is 1.75×106V/m,FEisrole="math" localid="1648932697397" 2.8×10-13NandFBis1.6×1013N

Step by step solution

01

Figure for direction of electric field intensity is depicted.

Figure is,

The figure on the page has come to an end is,

02

Calculation for force

Magnetic and electric fields both produce force:

tan30°=FBFE

A magnetic force occurs upward when utilizing the right hand rule.

FB=qvB

FB=1.6×10-19×107×0.1

FB=1.6×10-13N

For FE:

tan30°=FBFE=1.6×1013FE

FE=1.6×10-130.57

FE=2.8×10-13N

03

Calculation for electric field strength

Strength of the electric field,

FE=qE

E=FEq

FE-Force of electric field

q-charge

E=2.8×10-131.6×10-19

localid="1648932420433" E=1.75×106V/m

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