Chapter 31: Q. 32 (page 902)

An electron travels with $\vec{v} = 5.0 \times 10^{6} \hat{i} \frac{m}{s}$ through a point in space where $\vec{E} = (2.0 \times 10^{5} \hat{i} - 2.0 \times 10^{5} \hat{j}) \frac{V}{m}$ and $\vec{B} = - 0.10 \hat{k} T$ . What is the force on the electron?

Short Answer

Expert verified

The force on the electron will be $27 \times 10^{- 17} N$ .

Step by step solution

Given information

We have been given that an electron travels with $\vec{v} = 5.0 \times 10^{6} \hat{i} \frac{m}{s}$ through a point in space where $\vec{E} = (2.0 \times 10^{5} \hat{i} - 2.0 \times 10^{5} \hat{j}) \frac{V}{m}$ and localid="1650176818409" $\vec{B} = - 0.10 \hat{k} T$ .

We need to calculate the force on the electron.

Simplify

According to Lorentz force : $F = q (E + v \times B)$

Firstly we have to calculate the value of $v \times B$ .

$v \times B = 5 \times 10^{6} \hat{i} \times (- 0.10 \hat{k}) v \times B = - 5 \times 10^{5} \hat{j}$

Now,

$F = q (E + v \times B) F = q (2 \times 10^{5} \hat{i} - 2 \times 10^{5} \hat{j} - 5.0 \times 10^{5} \hat{j}) F = 1.6 \times 10^{- 19} (2 \times 10^{5} \hat{i} - 7 \times 10^{5} \hat{j}) F = 1.6 \times 10^{- 19} \times 1700 F = 27 \times 10^{- 17} N$

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An electron travels with $\vec{v} = 5.0 \times 10^{6} \hat{i} \frac{m}{s}$ through a point in space where $\vec{E} = (2.0 \times 10^{5} \hat{i} - 2.0 \times 10^{5} \hat{j}) \frac{V}{m}$ and $\vec{B} = - 0.10 \hat{k} T$ . What is the force on the electron?

Short Answer

Step by step solution

Given information

Simplify

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An electron travels with v→=5.0×106i^msthrough a point in space where E→=(2.0×105i^-2.0×105j^)Vmand B→=-0.10k^T. What is the force on the electron?

Short Answer

Step by step solution

Given information

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Dynamics

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Study anywhere. Anytime. Across all devices.

An electron travels with $\vec{v} = 5.0 \times 10^{6} \hat{i} \frac{m}{s}$ through a point in space where $\vec{E} = (2.0 \times 10^{5} \hat{i} - 2.0 \times 10^{5} \hat{j}) \frac{V}{m}$ and $\vec{B} = - 0.10 \hat{k} T$ . What is the force on the electron?